forfiles executes the command line after the /C option with the currently iterated directory as the working directory. This is also true with the /S option.
The reference @file returns the pure (quoted) file name; the reference @relpath returns a path relative to the given root (behind the /P option, which defaults to the current directory).
So you could try something like this (note that the cmd /C prefix is required for cmd-internal commands like move, echo or if; the upper-case ECHO just displays the move command line that would be executed without):
forfiles /S /D -90 /C "cmd /C if @isdir==FALSE ECHO move @relpath 0x22C:\temp\0x22"
This would move all files into the directory C:\temp, losing the original directory hierarchy however. (Note that the if @isdir==FALSE query prevents sub-directories from being processed.)
Therefore we need to build the destination directories on our own, like this:
forfiles /S /D -90 /C "cmd /C if @isdir==FALSE (for %F in (@relpath) do @(2> nul mkdir 0x22C:\temp\%~F\..0x22 & ECHO move @relpath 0x22C:\temp\%~F0x22))"
What happens here:
- in general,
0x22 represents a quotation mark ";
if @isdir==FALSE ensures to process files only;
- the
for loop just removes surrounding quotes from the path retrieved by @relpath when accessed by %~F; ensure to double the % signs in case you are using the code in a batch file!
mkdir creates the parent directory of the currently iterated item; 2> nul hides the error message in case the directory already exists;
move is preceded by ECHO for testing purposes; remove it to actually move files;
If you want to overwrite files in the destination location, simply add the /Y option to move.
The following command line might also work for the sample path, but it is going to fail for sure in case the destination path contains SPACEs or other poisonous characters, because quotation is not properly handled:
forfiles /S /C "cmd /C if @isdir==FALSE (2> nul mkdir C:\temp\@relpath\.. & ECHO move @relpath C:\temp\@relpath)"