Python - Else condition not executed

Question

Please check my code below, in that else condition matches (test data is "k"), but not executing the statement inside it, rather it gives error like -

NameError: name "k" is not defined.

at the same time if I give 8 or 9, it did not show the above error at the same time not executed the else statement as well, just showing the main menu again

from math import sqrt
def addition(firstNum,secondNum):
    total = firstNum+secondNum
    return total

def substraction(firstNum,secondNum):
    total = firstNum-secondNum
    return total

def multiplication(firstNum,secondNum):
    total = firstNum*secondNum
    return total

def division(firstNum,secondNum):
    total = firstNum/secondNum
    return total

def root(firstNum):
    total = (firstNum*firstNum)
    return total

menu={}
menu[" "] = "          --------PYTHON CALCULATOR-------            "
menu["."] = "~~Main Menu~~"
menu["1"] = "Addition"
menu["2"] = "Substraction"
menu["3"] = "Multiplication"
menu["4"] = "Division"
menu["5"] = "Square"
menu["6"] = "Root"
menu["7"] = "Exit\n"

while True:
    options = menu.keys()
    options.sort()
    for entry in options:
        print entry, menu[entry]

    selection = input("Please select your correct option: ")

    if selection   == 1:
        firstNum=input ("\nPlease enter first number : ")
        secondNum=input("Please enter Second number: ")

        print "Answer is " , addition(firstNum,secondNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 2:
        firstNum=input ("\nPlease enter first number : ")
        secondNum=input("Please enter Second number: ")
        print "Answer is " ,substraction(firstNum,secondNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 3:
        firstNum=input ("\nPlease enter first number : ")
        secondNum=input("Please enter Second number: ")
        print "Answer is ",multiplication(firstNum,secondNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 4:
        firstNum=input ("\nPlease enter first number : ")
        secondNum=input("Please enter Second number: ")
        print "Answer is " ,division(firstNum,secondNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 5:
        firstNum=input ("\nPlease enter first number : ")
        print "Answer is " ,sqrt(firstNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 6:
        firstNum=input ("\nPlease enter first number : ")
        print "Answer is " ,root(firstNum)
        print "--------------------------------------------------------\n\n"
    elif selection == 7:
        break
    else:
        "Invalid option keyed in..."

Use `raw_input` instead of `input`. But don't forget to convert the input to an int afterwards. — Aran-Fey, Mar 06 '17 at 10:00
Please see http://stackoverflow.com/questions/23294658/asking-the-user-for-input-until-they-give-a-valid-response to see how to get valid input. — PM 2Ring, Mar 06 '17 at 10:10

score 1 · Accepted Answer · edited May 23 '17 at 12:00

1

Use raw_input instead of input. Here's why. raw_input return the string entered by the user, you should then convert to int using:

firstnum = int(raw_input('...'))

edited May 23 '17 at 12:00

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answered Mar 06 '17 at 10:08

Python - Else condition not executed

1 Answers1