This is what i have so far:
n=int(input("Enter a number"))
for i in range (1,n+1,):
if(i%2==0):
print(i)
So for example, if the user enters 100, the program should print the following:
4
16
36
64
100
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TankorSmash
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python-help
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Your indentation is all wrong. – Barmar Mar 16 '17 at 20:39
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Read: [Formatting code in posts](http://stackoverflow.com/help/formatting) – Barmar Mar 16 '17 at 20:41
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Could you post the traceback? The indentation was wrong but that could have been you pasting it in wrong. – TankorSmash Mar 16 '17 at 20:41
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Instead of testing whether a number is a square, just generate all the squares. And you don't need to test if a number is even, because even squares are always the square of even numbers. So just increment by 2 instead of 1. – Barmar Mar 16 '17 at 20:46
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i tried incrementing by 2 instead of 1, but it didn`t work – python-help Mar 16 '17 at 20:50
1 Answers
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The ** operator in python acts as a power operator. So, x-squared is basically x**2, and x**0.5 is square root of x.
n = int(input("Enter a number"))
for i in range(2, n**0.5+1, 2):
print(i**2)
shad0w_wa1k3r
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1Use `range(2, n**0.5+1, 2)` so you step by 2 instead of 1. Then you don't need to test if `sqr` is even. – Barmar Mar 16 '17 at 20:47
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