Printing results without spaces python3

Question

def WhichAreCaps(Word):
    for w in Word:
        if w.isupper() == True:
          print (w)

WhichAreCaps("IJkdLenMd")

Result:

I
J
L
M

So I'm trying to build a code that finds Capitalized letters in a string and print out the letters. The problem is that I want the result to come out as one line of string, not four. Is there a way to do so? (I'm just a beginner;;)

See the [`print()`](https://docs.python.org/3/library/functions.html#print) documentation (especially the `end` argument). — glibdud, Mar 17 '17 at 12:21
@WillemVanOnsem I've tries doing print (" ".join(w)), still the same probelm — ChikkinMan, Mar 17 '17 at 12:25
BTW, your function would be more useful if it returns the results as a string instead of printing them. That way, the caller could print the results themself, or do some other processing on the results before printing them. — PM 2Ring, Mar 17 '17 at 12:28
@ChikkinMan Change approach: `"".join(c for c in word if c.isupper())`. — farsil, Mar 17 '17 at 12:29
You _could_ do this: `print(''.join(filter(str.isupper, word)))`, but you probably shouldn't. :) — PM 2Ring, Mar 17 '17 at 12:36
@PM2Ring How would it look like if it was returned? I have a hard time converting print() to return() — ChikkinMan, Mar 17 '17 at 12:37
Well, you put a `return` statement at the end of the function, once you've finished the processing and have collected the results into a list or string. Eg, you can change the last line of [Akshay Apte's answer](http://stackoverflow.com/a/42857468/4014959) from `print(ans)` to `return ans`. And then you could call it like `print(WhichAreCaps("IJkdLenMd"))`. Or doing it on separate lines `s = WhichAreCaps("IJkdLenMd")` `print(s)`. That way you can do other stuff with `s`. — PM 2Ring, Mar 17 '17 at 12:42

Mazdak · Accepted Answer · 2017-03-17T12:29:00.750

2

print function accepts an end keyword argument to specifies the end of the string after printing. By default it's set to new line (\n), you can simply use a space. Also note that checking the truths value of any expression with == True is wrong since True interprets as 1 and every thing that returns 1 will be interpreted as True. You can simply use if w.isupper():

def WhichAreCaps(Word):
    for w in Word:
        if w.isupper():
          print(w, end=' ')

Another way is yielding the vowels in your function and make it a generator:

def WhichAreCaps(Word):
    for w in Word:
        if w.isupper():
            yield w

Then you can join the result in any way you like and print it:

print(','.join(WhichAreCaps(Word)))

After all, as a more pythonic approach for this ask you can simply use a list comprehension within str.join:

print(' '.join([w for w in Word if w.isupper()]))

edited Mar 17 '17 at 12:29

answered Mar 17 '17 at 12:21

Mazdak

105,000
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I would clean it up with an empty `print()` just before i `return`. – Ma0 Mar 17 '17 at 12:22
@Ev.Kounis Thanks would be good to. – Mazdak Mar 17 '17 at 12:30
@Kasramvd Yup, used the end=" " and it worked.! Thank you! – ChikkinMan Mar 17 '17 at 12:31

Akshay Apte · Answer 2 · 2017-03-17T12:35:39.047

1

You can Just append the letters to an empty string and then return it.

def WhichAreCaps(Word):
    ans=''
    for w in Word:
        if w.isupper() == True:
          ans+=w
    print(ans)

edited Mar 17 '17 at 12:35

answered Mar 17 '17 at 12:23

Akshay Apte

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I do not understand the dv.. Can the downvoter explain? – Ma0 Mar 17 '17 at 12:29
1

@Ev.Kounis Maybe it's because it's a code-only answer. Or maybe the down-voter voted on the early version of the answer which used the Python 2 `print` statement and didn't notice that Akshay fixed that. – PM 2Ring Mar 17 '17 at 12:32
Thanks guys. I'm relatively new to SO. – Akshay Apte Mar 17 '17 at 12:36
I downvoted because 1) it's a code only answer, 2) `== True` is redundant, and mostly 3) I don't condone string concatenation because it's underperformant. – Jean-François Fabre Mar 17 '17 at 15:00

Printing results without spaces python3

2 Answers2