printf("%.0lf\n", x); is not required to print the exact value of (double) x.
A compliant C compiler/standard C library will generate code that will print about DBL_DECIMAL_DIG (typically 17), correct significant decimal digits.  Other may print more digits correctly.  (Mine printed 9223372036854775808).  See <float.h>
// 45678901234567
9223372036854775800 // answer
9223372036854775808 // true answer:
Extreme example
DBL_MAX may have the exact value of 
179769313486231570814527423731704356798070567525844996598917476803157260780028538760589558632766878171540458953514382464234321326889464182768467546703537516986049910576551282076245490090389328944075868508455133942304583236903222948165808559332123348274797826204144723168738177180919299881250404026184124858368
Yet many results of printf("%.0lf\n" ,DBL_MAX); will report zeros after a certain point
179769313486231570814527423731704356798070600000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000
OP later added that the reference pow() function was long long int pow(long long int a, long long int b).  pow_ll_version(2,63) would be expected to result in 9223372036854775808, which is 1 passed many LLONG_MAX - certainly undefined behavior.  Let us assume it wrapped to -9223372036854775808, and was printed with  printf("%llu\n" , long_long_int_result); (more UB as mis-matched specifier and type).  This may have given 9223372036854775808 to OP.  
printf() output of integers is exact, not so with floating point values.