PHP Function not available on another page

Asked Mar 23 '17 at 20:43

Active Mar 23 '17 at 22:06

Viewed 28 times

I am trying to get a function to output on a page on my site.

All my functions are in functions.php, which I include in the head on all pages.

Here is an example function:

function get_username(){
    $userID = $_SESSION['user'];
    if($userID){
        $username = mysqli_query($dbconfig,"SELECT * FROM users WHERE userId='$userID'");
        while($row = mysqli_fetch_assoc($username)) {
            return $row['userName'];    
        }
    }
}

When calling the function get_username nothing is returned. To verify, I print the session to check the data exists, which it does.

I have also tried just echoing a simple word in the function like this:

function get_username(){
    echo 'test';
}

Again nothing is outputted. As mentioned above the functions.php is included in the head of the page.

Any ideas?

edited Mar 23 '17 at 22:06

henrycarteruk

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asked Mar 23 '17 at 20:43

danyo

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http://php.net/manual/en/function.error-reporting.php --- http://php.net/manual/en/mysqli.error.php – Funk Forty Niner Mar 23 '17 at 20:44
You also should look into variable scope: http://php.net/manual/en/language.variables.scope.php – jeroen Mar 23 '17 at 20:45
... http://stackoverflow.com/q/16959576/1415724 which is what @jeroen meant. Edit: Oh, you edited lol – Funk Forty Niner Mar 23 '17 at 20:45
@Fred-ii- Just added a link as well :-) – jeroen Mar 23 '17 at 20:46
1

@jeroen I edited my comment about your edit lol – Funk Forty Niner Mar 23 '17 at 20:46
1

You generally shouldn't return inside a loop. That will end the loop, so you'll only return the value from the first row. You should collect all the results into an array, and return the array after the loop. If the query only returns 1 row, you don't need a loop in the first place. – Barmar Mar 23 '17 at 20:49

PHP Function not available on another page

0 Answers0