a = [0, 0, 0, 0, 1, 0, 0]
b = [0, 0, 0, 0]
I want to remove the [0, 0, 0, 0] from list a.
How do I do this?
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Are the elements to be removed or the list that fits (in exact order)? Related? - https://stackoverflow.com/questions/4211209/remove-all-the-elements-that-occur-in-one-list-from-another – shad0w_wa1k3r Apr 02 '17 at 06:03
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the list that fits in exact order needs to be removed – Phoebe Apr 02 '17 at 06:03
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Is it indeed a list of 0s and 1s? – DYZ Apr 02 '17 at 06:06
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yes it is! it is a list of 0s and 1s – Phoebe Apr 02 '17 at 06:07
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Is there more than one instance of `b` in `a`? – DYZ Apr 02 '17 at 06:08
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no, there's only one instance of b in a – Phoebe Apr 02 '17 at 06:11
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1Possible duplicate of [python remove elements of list from another list WITH MULTIPLE OCCURRENCES of items in both](http://stackoverflow.com/questions/38544296/python-remove-elements-of-list-from-another-list-with-multiple-occurrences-of-it) – MotKohn Apr 02 '17 at 06:33
1 Answers
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Convert each list to a string:
a1 = ''.join('1' if x else '0' for x in a)
b1 = ''.join('1' if x else '0' for x in b)
Find the start index of b1 in a1:
start = a1.index(b1)
The end index is start index plus the length of b1:
end = start + len(b1)
Now, extract the original list fragments before start and after end and combine them:
newlist = a[:start] + a[end:]
DYZ
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Note that I incorrectly used `start+end` instead of `end` in the last line, and it worked because `start==0`. The answer is now fixed. – DYZ Apr 02 '17 at 06:33