You can utilize the .sort() method:
>>> id.sort()
['5566FT6N', '6LDFTLL9', '6P4EF7BB', '6RHSDD46', '6UVSCF4H', '6VPZ4T5P', '6YYPH399', '7SKDEZWE', 'EHYXE34N', 'N9RFERBG', 'TT56GTN2']
This will sort the list in place. If you don't want to change the original id list, you can utilize the sorted() method
>>> sorted(id)
['5566FT6N', '6LDFTLL9', '6P4EF7BB', '6RHSDD46', '6UVSCF4H', '6VPZ4T5P', '6YYPH399', '7SKDEZWE', 'EHYXE34N', 'N9RFERBG', 'TT56GTN2']
>>> id
['6LDFTLL9', 'N9RFERBG', '6RHSDD46', '6UVSCF4H', '7SKDEZWE', '5566FT6N', '6VPZ4T5P', 'EHYXE34N', '6P4EF7BB', 'TT56GTN2', '6YYPH399']
Notice, with this one, that id is unchanged.
For a DataFrame, you want to use sort_values().
df.sort_values(0, inplace=True)
0 is either the numerical index of your column or you can pass the column name (eg. id)
           0
5   5566FT6N
0   6LDFTLL9
8   6P4EF7BB
2   6RHSDD46
3   6UVSCF4H
6   6VPZ4T5P
10  6YYPH399
4   7SKDEZWE
7   EHYXE34N
1   N9RFERBG
9   TT56GTN2