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This is what I have so far. I have been testing it on c++ shell and it gives me error.

#include <iostream>
    #include <string>

    int main() {

    cout << "Enter a number between 3 and 12: ";
    int n;
    cin >> n;

    if(n>=3 && n<=12)
      cout<<"Good number."endl;
    else
      cout<<"Bad number"endl;

    return 0; //indicates success
    }//end of main
BhandariS
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jungjaehyun0214
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1 Answers1

4

cout,cinand endl are part of the standard library so you need to use std::cout, std::cin and std::endl. You can use using namespace std; on the beginning as well (after the includes, but it is considered as bad programming style). Change your output to:

std::cout << "Good number." << std::endl;

Here is a working example:

int main() {

    std::cout << "Enter a number between 3 and 12: ";
    int n;
    std::cin >> n;

    if(n>=3 && n<=12)
      std::cout<<"Good number."<<std::endl;
    else
      std::cout<<"Bad number"<<std::endl;

    return 0; //indicates success
}
izlin
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