How to remove only item of array?

Question

I have an array.

$a_input = array(1,2,3,4,5)

I want to remove 1 from array . out put is :

array(2,3,4,5);

remove 2 => output:

array(1,3,4,5);

remove 3 => output :

array(1,2,4,5);

..... how to do this with for loop ?

Answer 1

use unset.

foreach($a_input as $key => $val){
   if($a_input[$key]==1) unset($a_input[$key]); 
}

Answer 2

try this

$a_input = array(1,2,3,4,5);

$cnt=count($a_input);
for($i=0;$i<$cnt;$i++){
   $remove = array($i+1);
   $output1=array_diff($a_input,$remove);
   var_dump("<pre>",$output1);
}

Online test

Answer 3

You can use

$array = array(1,2,3,4,5);
if (($key = array_search('1', $array)) !== false) {
unset($array[$key]);
}

Answer 4

Here we are searching a value in the array If it is present, then proceed to get the key at which required value is present, then unseting that value.

Try this code snippet here

<?php
ini_set('display_errors', 1);

$a_input = array(1,2,3,4,5);
$numberToSearch=2;

if(in_array($numberToSearch,$a_input))//checking whether value is present in array or not.
{
    $key=array_search($numberToSearch, $a_input);//getting the value of key.
    unset($a_input[$key]);//unsetting the value
}
print_r($a_input);

Output:

Array
(
    [0] => 1
    [2] => 3
    [3] => 4
    [4] => 5
)

Answer 5

What you need is array_filter:

$input = array(1,2,3,4,5)
$remove = 1;
$result = array_filter($input, function ($val) use ($remove) {
  return $val !== $remove;
});

Answer 6

You need array_diff.

$a_input = array(1,2,3,4,5);

you can create new array with values like below:

$remove = array(1,2);

$result=array_diff($a_input,$remove);

output:

array(3,4,5);

Most of the programmer use this way only.And this will work for multiple elements also.