Exclude specific keys of dict when passing to variable

Question

im trying to exclude some key when passing a dict to a variable. for example.

dict1 = {
    'id': 1,
    'name' : 'John Woe',
    'flag' : True,
    'position' : 'Developer'
}

Now i would like to exclude the key flag or any specified keys when passing it to dict2 variable. Normally i can simple hardcodedly assign it but i want a dynamic approach.

Such as this:

dict2 = dict1.exclude(['flag', 'position'])

khachik · Accepted Answer · 2017-04-25T18:54:32.087

5

keys_to_exclude = set(('flag',))
dict2 = {k:v for k,v in dict1.iteritems() if k not in keys_to_exclude}

As a response to the criticism in the comments about this being O(MN) - keys_to_exclude can be a set and it will make it O(N) with less burden to garbage collection, compared to copy/pop solution.

edited Apr 25 '17 at 18:54

answered Apr 25 '17 at 18:40

khachik

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it is possible to exclude 1 or more keys? – Shift 'n Tab Apr 25 '17 at 18:41
@ShiftN'Tab yes, see my update. – khachik Apr 25 '17 at 18:42
Do you know if doing `dict1.copy()` and then `dict2.pop('flag')` could be more efficient in case of dicts with a large number of keys? – VMRuiz Apr 25 '17 at 18:42
@VMRuiz i think it is ok because it can help with many keys in just 2 line of codes. – Shift 'n Tab Apr 25 '17 at 18:45
I mean its O(N) vs O(MN), but it really depends on the use cases, and that is outside the scope of the question at hand – Fallenreaper Apr 25 '17 at 18:46
I find this answer hepful :) – Shift 'n Tab Apr 25 '17 at 18:48
1

For Python 3 use dict.items() instead of dict.iteritems() – Tom Roth May 17 '22 at 02:04

Exclude specific keys of dict when passing to variable

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