how call method varargs or (int...args) in main class giving arguments at command line

Question

public class VarGreet {

   public static void main(String[] args) {
        // TODO code application logic here

         printGreeting(args[0],args);
    }
    public static void printGreeting(String s, Integer...id) {
         for (Integer n : names) {
              System.out.println("Hello " + n + ". "); 
         }
    }
}

`args` is an array of `Strings` change --> `Integer...id` to `String...id`, where is `names` declared ?. that aside what is the problem? what is your question? due to those reasons I am voting to close this question for "unclear what you're asking" — Ousmane D., Apr 27 '17 at 20:33
Possible duplicate of [How to convert a String to an int in Java?](http://stackoverflow.com/questions/5585779/how-to-convert-a-string-to-an-int-in-java) — Joe C, Apr 27 '17 at 20:35
how could i pass input to Integer...id in main, when i call the PrintGreeting — manish, Apr 27 '17 at 22:15

score 0 · Accepted Answer · answered Apr 27 '17 at 20:58

In printGreeting you are looping over names (not id). Fix that first,

for (Integer n : id) {
    System.out.println("Hello " + n + ". ");
}

Then, assuming you are using Java 8+, you can start with the second argument and map everything to an Integer, collect that as a List and then convert that to an Integer[] like

printGreeting(args[0], Stream.of(args).skip(1).mapToInt(Integer::parseInt)
        .boxed().collect(Collectors.toList()).toArray(new Integer[] {}));

how call method varargs or (int...args) in main class giving arguments at command line

1 Answers1