Random numbers in Unity C#

Question

Here is my code:

public class RandomNumbers : MonoBehaviour {
    public Transform mCanvas;
    public Text[] numbers;
    int idx = 0;

    void Start()
    {
        StartCoroutine("CreateNum"); 
    }

    IEnumerator CreateNum()
    {
        while (idx < numbers.Length)
        {
            Text g = Instantiate(numbers[idx], new Vector3(Random.Range(-100, 100), Random.Range(-100, 100), 0), Quaternion.identity);
            g.transform.SetParent(mCanvas, false);
            yield return new WaitForSeconds(2f);
            Destroy(g);
            ++idx;
        }
    }
}

This code makes 4 texts appear in ascending order on the screen. I want these four numbers to appear not in increasing but random form.

http://stackoverflow.com/questions/13457917/random-iteration-in-for-loop — StijnvanGaal, Apr 28 '17 at 09:33
@StijnvanGaal actually http://stackoverflow.com/questions/273313/randomize-a-listt would be more approprate. The op needs to shuffle his numbers. — Scott Chamberlain, Apr 28 '17 at 15:31

score 2 · Accepted Answer · answered Apr 28 '17 at 15:34

What you need to do is shuffle the array of numbers so they are in a random order, then you can grab in order the randomized list and it acts the same as picking items at random without duplicating.

public class RandomNumbers : MonoBehaviour {
    public Transform mCanvas;
    public Text[] numbers;
    int idx = 0;

    void Start()
    {
        //Randomizes the list of numbers
        Shuffle(numbers);

        StartCoroutine("CreateNum"); 
    }

    IEnumerator CreateNum()
    {
        while (idx < numbers.Length)
        {
            Text g = Instantiate(numbers[idx], new Vector3(Random.Range(-100, 100), Random.Range(-100, 100), 0), Quaternion.identity);
            g.transform.SetParent(mCanvas, false);
            yield return new WaitForSeconds(2f);
            Destroy(g);
            ++idx;
        }
    }

    //This is called a Fisher-Yates shuffle https://en.wikipedia.org/wiki/Fisher%E2%80%93Yates_shuffle
    //This function can be used with any Array or List you send it.
    private static void Shuffle<T>(IList<T> list)  
    {  
        int n = list.Count;  
        while (n > 1) {  
            n--;  
            int k = Random.Range(0, n + 1);  
            T value = list[k];  
            list[k] = list[n];  
            list[n] = value;  
        }  
    }

}

Well now I added a bool that sets the limit of numbers to appear.... How to make these 3 or 4 or 9 numbers to appear to gather? — Gheorghe C., Apr 29 '17 at 07:21
For example, the screen shows number 2 then 4 then 8. And then they will multiply or gather — Gheorghe C., Apr 29 '17 at 07:23

Random numbers in Unity C#

1 Answers1