Trying to parse XML response in Python

Question

I am trying to obtain the value of 2 elements (Result and AuthenticationKey)from this XML. The <s:Envelope> syntax is throwing me off.

<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
   <s:Body>
      <AuthenticateResponse xmlns="http://remote.Services">
         <AuthenticateResult xmlns:a="http://schemas.datacontract.org/2004/07/remote.Services.Api.DataContracts" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
            <AdditionalInfo i:nil="true"/>
            <ErrorMessage i:nil="true"/>
            <ErrorMessageId i:nil="true"/>
            <ErrorMessages i:nil="true" xmlns:b="http://schemas.microsoft.com/2003/10/Serialization/Arrays"/>
            <InternalId>0</InternalId>
            <RecordsAffected>0</RecordsAffected>
            <Result>true</Result>
            <WarningMessages i:nil="true" xmlns:b="http://schemas.microsoft.com/2003/10/Serialization/Arrays"/>
            <a:AuthenticationKey>SUPERSECRETTOKEN</a:AuthenticationKey>
            <a:UserGrpId>YYY</a:UserGrpId>
            <a:UserId>XXX</a:UserId>
         </AuthenticateResult>
      </AuthenticateResponse>
   </s:Body>
</s:Envelope>

Here is the relevant line of code that is returning a None. Both lines of code are returning a None.

I tried to use the code from another question on stackoverflow, but I am not sure on how to introduce the namespaces in the find method for this particular xml.

tree = ElementTree.fromstring(resp.text)
    token = tree.find("AuthenticateResponse") #Option1
    token = tree.find("Envelope/Body/AuthenticateResponse/AuthenticateResult/AuthenticationKey") #Option2
    print token

Possible duplicate of http://stackoverflow.com/questions/14853243/parsing-xml-with-namespace-in-python-via-elementtree — Milo, May 02 '17 at 13:48

score 0 · Accepted Answer · edited May 23 '17 at 12:18

The xmlns part becomes a prefix for your tags, i.e. to find AuthenticateResponse you would need to search for {http://remote.Services}AuthenticateResponse.

print(list(tree)[0].find('{http://remote.Services}AuthenticateResponse'))
>>> <Element '{http://remote.Services}AuthenticateResponse' at 0x00000000027228B8>

For a more general solution have a look at the answer here.

from io import StringIO
tree = ET.iterparse(StringIO("""<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
   <s:Body>
      <AuthenticateResponse xmlns="http://remote.Services">
         <AuthenticateResult xmlns:a="http://schemas.datacontract.org/2004/07/remote.Services.Api.DataContracts" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
            <AdditionalInfo i:nil="true"/>
            <ErrorMessage i:nil="true"/>
            <ErrorMessageId i:nil="true"/>
            <ErrorMessages i:nil="true" xmlns:b="http://schemas.microsoft.com/2003/10/Serialization/Arrays"/>
            <InternalId>0</InternalId>
            <RecordsAffected>0</RecordsAffected>
            <Result>true</Result>
            <WarningMessages i:nil="true" xmlns:b="http://schemas.microsoft.com/2003/10/Serialization/Arrays"/>
            <a:AuthenticationKey>SUPERSECRETTOKEN</a:AuthenticationKey>
            <a:UserGrpId>YYY</a:UserGrpId>
            <a:UserId>XXX</a:UserId>
         </AuthenticateResult>
      </AuthenticateResponse>
   </s:Body>
</s:Envelope>"""))
for _, element in tree:
    element.tag = element.tag.split('}')[-1]

print(tree.root.find('Body').find('AuthenticateResponse').find('AuthenticateResult').find('AuthenticationKey').text)
>>> 'SUPERSECRETTOKEN'

Trying to parse XML response in Python

1 Answers1