decode json into php variables

Question

I am trying to get the contents of a JSON result into php variables. The code I am using is:

$request = json_decode(file_get_contents("https://api.sunrise-sunset.org/json?lat=51.507351&lng=-0.127758&date=today"), true);

The output of the JSON call looks like this:

array(2) { 
     ["results"]=> array(10) { 
         ["sunrise"]=> string(10) "4:21:35 AM" 
         ["sunset"]=> string(10) "7:32:34 PM" 
         ["solar_noon"]=> string(11) "11:57:04 AM" 
         ["day_length"]=> string(8) "15:10:59"
         ["civil_twilight_begin"]=> string(10) "3:42:08 AM"
         ["civil_twilight_end"]=> string(10) "8:12:01 PM"
         ["nautical_twilight_begin"]=> string(10) "2:49:55 AM" 
         ["nautical_twilight_end"]=> string(10) "9:04:14 PM" 
         ["astronomical_twilight_begin"]=> string(10) "1:41:12 AM" 
         ["astronomical_twilight_end"]=> string(11) "10:12:57 PM" 
      } 
      ["status"]=> string(2) "OK" 
}

How can I get the "sunrise" time and the "sunset" times into php variables $SunRiseTime and $SunSetTime;

Many thanks in advance for your time.

`echo json_decode($json,true)["results"]["sunrise"];` and `echo json_decode($json,true)["results"]["sunset"];` — Sahil Gulati, May 06 '17 at 15:33

Sahil Gulati · Accepted Answer · 2017-05-06T15:41:49.450

1

Simple and straight.

<?php
ini_set('display_errors', 1);

$json = file_get_contents("https://api.sunrise-sunset.org/json?lat=51.507351&lng=-0.127758&date=today"); 
$array=json_decode($json,true);

echo $SunRiseTime=$array["results"]["sunrise"];
echo $SunSetTime=$array["results"]["sunset"];

Output: 4:21:35 AM 7:32:34 PM

edited May 06 '17 at 15:41

answered May 06 '17 at 15:37

Sahil Gulati

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perfect, thats just what I needed. Many thanks to all that replied. – DCJones May 06 '17 at 15:40
@DCJones welcome ... :) – Sahil Gulati May 06 '17 at 15:41
I will as soon the system will let me, thanks. – DCJones May 06 '17 at 15:43

LF00 · Answer 2 · 2017-05-06T15:38:29.073

0

use $$ to define a variable in php dynamic. If your want to static define a variable, directly assign the value to it.

dynamic,

$name = 'SunRise';
$$name = $array["results"]["sunrise"];

static name,

$SunRise = $array["results"]["sunrise"];

edited May 06 '17 at 15:38

answered May 06 '17 at 15:33

LF00

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Why not just directly use `$SunRise`? – inarilo May 06 '17 at 15:34
For this is maybe dynamic. if this is static you're right. – LF00 May 06 '17 at 15:35
1

appears to be static – inarilo May 06 '17 at 15:37

score 0 · Answer 3 · answered May 06 '17 at 15:38

0

$SunRiseTime = $request['results']['sunrise'];
$SunSetTime  = $request['results']['sunset'];

answered May 06 '17 at 15:38

inarilo

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decode json into php variables

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