How system give me negative number?

Asked May 09 '17 at 08:12

Active May 09 '17 at 08:12

Viewed 51 times

for(int i = 0;i<=33;i++){
        System.out.println(i+" "+(i<<i)+" "+Integer.toBinaryString(1<<i));
        //31 -2147483648 10000000000000000000000000000000
    }

When ibecome 31 it give me a negative number,if it's because out of bound , then what happened at that time? thanks a lot!

asked May 09 '17 at 08:12

wylasr

3

[two's complement](https://en.wikipedia.org/wiki/Two%27s_complement) – Sergey Kalinichenko May 09 '17 at 08:14
This must be a duplicate, but what is happening is that at `i=31` you start flipping the sign bit of that integer. Hence, it appears negative. – Tim Biegeleisen May 09 '17 at 08:14
2

The top bit of a *signed* int is the sign. The sign has to be represented somehow. – Peter Lawrey May 09 '17 at 08:17
@Tim Biegeleisen I know that, but it's still not very clear. – wylasr May 09 '17 at 08:19

How system give me negative number?

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