Regular Expression for minimum value 18 and maximum 99 with leading zero

Question

Regular Expression for minimum value 18 and maximum 99 with leading zero. Means my number should be from 18 to 99. With one condition of leading zero i.e 18 == 018, 99 == 099

If your allowable values are 18-99, how does a leading zero fit in to this? — AndrewR, May 13 '17 at 06:27
@Mykola Borysyuk I want this (v> 17 && v < 100) condition in regex. — Himanshu Shekhar, May 13 '17 at 06:28

score 6 · Accepted Answer · edited May 13 '17 at 06:39

6

Try this it will help you

Less than 18 and greater than 99 is not allowed

^(1[89]|[2-9][0-9])$

edited May 13 '17 at 06:39

anubhava

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answered May 13 '17 at 06:28

Shoaib Quraishi

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This does not address the criteria regarding leading zero – Jaromanda X May 13 '17 at 06:43
Am trying to enter value only between 0 to 1000 (including 0 and 1000). but its not working. Am using this regex `/^0?1[01]|0?[0-9][0-9][0-9]$/ ` – Karthikeyan Jul 04 '19 at 18:16

AndrewR · Answer 2 · 2017-05-13T15:48:35.860

4

^0?1[89]|0?[2-9][0-9]$

^ - beginning of string
0? - allow beginning 0
1[89] - match first character 1 and second 8 or 9
| - or
0? - allow beginning 0
[2-9] - match first character 2-9
[0-9] - match second character 0-9
$ - end of string

edited May 13 '17 at 15:48

answered May 13 '17 at 06:33

AndrewR

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that won't allow 099 (and surely \d ) – Jaromanda X May 13 '17 at 06:36

Gurmanjot Singh · Answer 3 · 2017-05-13T17:24:57.010

1

Try this:-

^0?(1[89]|[2-9]\d)$

Demo: https://regex101.com/r/CrcbHN/1

edited May 13 '17 at 17:24

answered May 13 '17 at 06:55

Gurmanjot Singh

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well, `0?(1[89]|[2-9]\d)` is just as good :p (you'll also need ^ and $ to truly "validate" – Jaromanda X May 13 '17 at 07:00
Sure, but https://regex101.com/r/ht2mil/3 works just as well, with four less characters (i.e. the extra () ()) – Jaromanda X May 13 '17 at 07:17
I am glad that worked :) I have recently started learning about regex. – Gurmanjot Singh May 13 '17 at 07:23

score 0 · Answer 4 · answered May 13 '17 at 06:56

0

(01[89])|(0[2-9]\d)

(01[89]) matches 018 to 019
(0[2-9]\d) matches 020 to 099

answered May 13 '17 at 06:56

voskhod

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no, that requires a leading 0, not optional as stated in the request for code - I mean, question – Jaromanda X May 13 '17 at 06:57
But leading zero _is_ required in question, isn't it? – voskhod May 13 '17 at 07:02
I took `With one condition of leading zero` to mean, in English `with one optional leading zero` - but you're probably right :p – Jaromanda X May 13 '17 at 07:05

Abhishek Gurjar · Answer 5 · 2017-05-13T07:00:43.333

0

Try with below,

0([1][89]|[2-9][0-9])

DEMO

edited May 13 '17 at 07:00

answered May 13 '17 at 06:56

Abhishek Gurjar

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`[0-9]+` a) what's wrong with \d - and b) that would allow, say 029631027910246741584 – Jaromanda X May 13 '17 at 06:58
@JaromandaX You are right on b) part I am working on it for \d see here http://stackoverflow.com/questions/6479423/does-d-in-regex-mean-a-digit – Abhishek Gurjar May 13 '17 at 06:59
ahh, I see the issue with \d (though, not sure how JS handles \d but you have an excellent point about it) – Jaromanda X May 13 '17 at 07:02

Regular Expression for minimum value 18 and maximum 99 with leading zero

5 Answers5