Im trying to delete all words from a list that include duplicate letters (to start with 'd' and 'r' for testing) but cannot get it check all the letters i want it to.
a = ["word","worrd","worrrd","wordd"]
alpha = ['d','r']
i = 0
x = 0
while x in range(0, len(alpha)):
while i in range(0, len(a)):
if a[i].count(alpha[x]) > 1:
del(a[i])
i = i - 1
else:
i = i + 1
x = x + 1
print(a)
Short solution using re.search() function:
import re
a = ["word","worrd","worrrd","wordd"]
result = [w for w in a if not re.search(r'([dr]).*\1', w)]
print(result)
The output:
[word]
([dr]).*\1 - regex pattern to check if some letter from character class [dr] occurs at least twice within a word
.* - matches 0 or more characters
\1 - points to the first captured group (...)
Another short alternative is using built-in all() function:
a = ["word","worrd","worrrd","wordd"]
alpha = ['d','r']
result = [w for w in a if all(w.count(c) == 1 for c in alpha)]
print(result)
This is your method only except I just added i = 0 after first while loop
a = ["word","worrd","worrrd","wordd"]
alpha = ['d','r']
i = 0
x = 0
while x in range(0, len(alpha)):
i = 0
while i in range(0, len(a)):
if a[i].count(alpha[x]) > 1:
del(a[i])
i = i - 1
else:
i = i + 1
x = x + 1
print(a)
['word']
you doing it right but you forgot to reset the value of "i" in while loop of x
a = ["word","worrd","worrrd","wordd"]
alpha = ['d','r']
x = 0
while x in range(0, len(alpha)):
# i should be reset here
i = 0
while i in range(0, len(a)):
if a[i].count(alpha[x]) > 1:
del(a[i])
i = i - 1
else:
i = i + 1
x = x + 1
print(a)
What you likely are after, is when you have two d:s or r:s in a row. Then you want a regex as:
import re
a = ["word","worrd","worrrd","wordd", "worded"]
result = [w for w in a if not re.search(r'(dd)|(rr)', w)
print(result)
