How to create metaclasses with dynamically named bases?

Question

here is my code:

class Tb(object):
    def __init__(self, name):
        self.name=name
    def foo(self):
        return 0

class Tb1(Tb):
    def foo(self):
        return 1

met=type('Tb1', (Tb1,), {})
a=met('aaa')

print(a.foo())

Is there any way to use dynamically named bases here:met=type('Tb1', (Tb1,), {}) like met=type('Tb1', (STRING_CLASS_NAME OR? ,), {})

score -1 · Answer 1 · answered May 15 '17 at 11:52

-1

I found an answer:

met=type('Tb1', (eval('Tb1'),), {})

answered May 15 '17 at 11:52

Vladimir Akkerman

131
3
14

Don't use `eval()`. You could just use `base = (Tb1,)` somewhere (and `type(name, base, {})`, or if you must use strings, see the duplicate. – Martijn Pieters May 15 '17 at 12:39
I need a string value (dynamic), so I can't use your variant. – Vladimir Akkerman May 16 '17 at 03:13
Yes, which is why I pointed to the duplicate. – Martijn Pieters May 16 '17 at 06:54

How to create metaclasses with dynamically named bases?

1 Answers1