how to get weekday from a given date in python?

Question

2001-10-18 I want to calculate weekday e.g. Monday, Tuesday from the date given above. is it possible in python?

http://stackoverflow.com/questions/9847213/which-day-of-week-given-a-date-python check this one out — Norbert Forgacs, May 19 '17 at 12:20
Possible duplicate of [which day of week given a date python](http://stackoverflow.com/questions/9847213/which-day-of-week-given-a-date-python) — gonczor, May 19 '17 at 12:20

score 11 · Accepted Answer · answered May 19 '17 at 12:26

11

Here is one way to do this:

dt = '2001-10-18'
year, month, day = (int(x) for x in dt.split('-'))    
answer = datetime.date(year, month, day).weekday()

answered May 19 '17 at 12:26

Amit Wolfenfeld

603
7
9

You can just use `format` to convert ISO datetime. – Cyzanfar Mar 15 '21 at 20:51

score 6 · Answer 2 · edited Nov 14 '19 at 17:55

6

There is the weekday() and isoweekday() methods for datetime objects.

Python doc

edited Nov 14 '19 at 17:55

ChaimG

7,024
4
38
46

answered May 19 '17 at 12:23

Alix Eisenhardt

313
2
10

score 0 · Answer 3 · edited Sep 30 '22 at 16:12

Here's what I have that got me if a leap year and also days in a given month (accounts for leap years). Finding out a specific day of the week, that I'm also stuck on.

def is_year_leap(year):
    if (year & 4) == 0:
        return True
    if (year % 100) == 0:
        return False
    if (year % 400) == 0:
        return True
    return False

def days_in_month(year, month):
    if month == 1 or month == 3 or month == 5 or month == 7 or month == 8 or month == 10 or month == 12:
        return 31
    if month == 2:
        if is_year_leap(year):
            return 29
        else:
            return 28
    if month == 4 or month == 6 or month == 9 or month == 11:
        return 31

how to get weekday from a given date in python?

3 Answers3

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