How to get the html-source of a website from a url (android, java)?

Question

I'm making a simplified app with only one EditText where a user enters an URL address and a Button "download". When the user clicks on the button, the app should download a source of given website and print it on the screen. How can I do it? Or where I should start looking for a solution?

Answer 1

First give permission in your Manifest file for INTERNET as

<uses-permission android:name="android.permission.INTERNET" />

Here is your layout

    <?xml version="1.0" encoding="utf-8"?>
    <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical" android:layout_width="match_parent"
    android:layout_height="match_parent">

    <LinearLayout
        android:orientation="horizontal"
        android:layout_width="match_parent"
        android:layout_height="wrap_content">

        <EditText
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:id="@+id/et_url"
            android:layout_gravity="center_horizontal" />
    </LinearLayout>

    <LinearLayout
        android:orientation="horizontal"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_weight="1"
        android:layout_gravity="bottom">

        <LinearLayout
            android:orientation="vertical"
            android:layout_width="match_parent"
            android:layout_height="match_parent"
            android:layout_weight="1">

            <Button
                android:layout_width="233dp"
                android:layout_height="58dp"
                android:text="New Button"
                android:id="@+id/downloadImage"
                android:layout_gravity="center"
                android:background="@color/blue"
                android:clickable="true" />
        </LinearLayout>

        <LinearLayout
            android:orientation="vertical"
            android:layout_width="145dp"
            android:layout_height="58dp">

            <ImageView
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:id="@+id/imageView786" />
        </LinearLayout>
    </LinearLayout>

    <LinearLayout
        android:orientation="horizontal"
        android:layout_width="match_parent"
        android:layout_height="45dp">

    </LinearLayout>
</LinearLayout>

Here is your Activity

public class Download extends Activity {
Button bt;
ImageView iv;
EditText et;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.download);
    bt = (Button)findViewById(R.id.downloadImage);
    et = (EditText )findViewById(R.id.et_url);
    iv = (ImageView)findViewById(R.id.imageView786);
    bt.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            DownloadImageFromPath(et.getText().toString());
        }
    });

}
public void DownloadImageFromPath(String path){
    InputStream in =null;
    Bitmap bmp=null;
    //ImageView iv = (ImageView)findViewById(R.id.imageView786);
    int responseCode = -1;
    try{

        URL url = new URL(path);//"http://192.xx.xx.xx/mypath/img1.jpg
        HttpURLConnection con = (HttpURLConnection)url.openConnection();
        con.setDoInput(true);
        con.connect();
        responseCode = con.getResponseCode();
        if(responseCode == HttpURLConnection.HTTP_OK)
        {
            //download
            in = con.getInputStream();
            bmp = BitmapFactory.decodeStream(in);
            in.close();
            iv.setImageBitmap(bmp);
        }

    }
    catch(Exception ex){
        Log.e("Exception", ex.toString());
    }
}

Now if u will give url as in edit text https://i.stack.imgur.com/MB4VU.jpg It will show the image