how can i map one list with keys and others lists with values into a dictionary

Question

I want to make a dictionary which contains sub-dictionaries

K = ['k1', 'k2', 'k3']  # key list
A = [['v1', 'v2', 'v3'], ['1', '2', '3']]  #value list
list_dict = ['dict1', 'dict2']
D = {d : {} for d in list_dict}

I want to do this:

D = {'dict1': {'k1': 'v1',
               'k2': 'v2',
               'k3': 'v3'},
     'dict2': {'k1': '1',
               'k2': '2',
               'k3': '3'}}

Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation. [on topic](http://stackoverflow.com/help/on-topic) and [how to ask](http://stackoverflow.com/help/how-to-ask) apply here. StackOverflow is not a design, coding, research, or tutorial service. You seem to be wanting someone to write your code for you, and that's not what we do here. — Prune, May 24 '17 at 16:29

inspectorG4dget · Answer 1 · 2017-05-24T17:57:49.487

1

In [70]: D = {d : dict(zip(K,v)) for d,v in zip(list_dict, A)}

In [71]: D
Out[71]: 
{'dict1': {'k1': 'v1', 'k2': 'v2', 'k3': 'v3'},
 'dict2': {'k1': '1', 'k2': '2', 'k3': '3'}}

edited May 24 '17 at 17:57

answered May 24 '17 at 16:34

inspectorG4dget

110,290
27
149
241

@omri_saadon Nah, that's what makes this *bad*. Should just use `dict(zip(K,v))` instead of `dict(zip(k,v))` with `k` repeatedly set to `K`. – Stefan Pochmann May 24 '17 at 17:09
@StefanPochmann: damn good catch! Why didn't I think of that?! – inspectorG4dget May 24 '17 at 17:57

score 0 · Answer 2 · answered May 24 '17 at 16:34

Try using:

answer = {list_dict[l]: {K[i]: A[l][i] for i in range(len(K))} for l in range(len(list_dict))}

This sets answer to a dictionary where the keys are all the items in list_dict. The values are then dictionaries generated by using every item in K mapped to the corresponding item in A[l] where l is the number of the key in list_dict.

answer is:

{
'dict1': 
    {'k3': 'v3',
     'k2': 'v2',
     'k1': 'v1'},
'dict2': 
    {'k3': '3',
     'k2': '2',
     'k1': '1'}
}

Hope this helps.

score 0 · Accepted Answer · answered May 24 '17 at 16:37

0

You can mix zip function with a dict as follow:

K = ['k1', 'k2', 'k3']  # key list
A = [['v1', 'v2', 'v3'], ['1', '2', '3']]  # value list
list_dict = ['dict1', 'dict2']
D = {}

for i in range(len(A)):
    D[list_dict[i]] = (dict(zip(K, A[i])))

print(D)

NB : it's very similar to : Map two lists into a dictionary in Python

answered May 24 '17 at 16:37

Nicolas M.

1,472
1
13
26

Thank you. This does the job too. – esenes221 May 25 '17 at 19:59

score 0 · Answer 4 · answered May 24 '17 at 16:45

0

Another method.

d = dict.fromkeys(list_dict)
for i, k in enumerate(sorted(d.keys())) :
    d[k] = {key:value for key, value in zip(K, A[i])}

answered May 24 '17 at 16:45

brodeur

96
5

how can i map one list with keys and others lists with values into a dictionary

4 Answers4