Initialize default Locale and Timezone with Spring configuration

Question

I'm loading application settings such as JDBC connection info from a properties file using PropertyPlaceholderConfigurer. I'd like to also have other settings such as default locale and timezone as properties.

But I'm unsure of the best method to execute Locale.setDefault() and TimeZone.setDefault(). I want them run early in startup and only once. Is there a proper way in Spring to execute some code FIRST, before other code is executed? Any suggestions?

I know I can specify default values on the command line, but this application will get installed in many places and I want to avoid problems caused by someone forgetting to specify -Duser.timezone=UTC or whatever.

score 12 · Answer 1 · answered Oct 30 '14 at 08:15

I found Spring loads some of its default beans including other beans before calling the contextInitialized method, so, here is a better approach "draft" that I can think of, let me know if you see any concern:

public class SystemPropertyDefaultsInitializer 
    implements WebApplicationInitializer{

    private static final Logger logger = Logger
            .getLogger(SystemPropertyDefaultsInitializer.class);

    @Override
    public void onStartup(ServletContext servletContext)
            throws ServletException {
        logger.info("SystemPropertyWebApplicationInitializer onStartup called");

        // can be set runtime before Spring instantiates any beans
        // TimeZone.setDefault(TimeZone.getTimeZone("GMT+00:00"));
        TimeZone.setDefault(TimeZone.getTimeZone("UTC"));

        // cannot override encoding in Spring at runtime as some strings have already been read
        // however, we can assert and ensure right values are loaded here

        // verify system property is set
        Assert.isTrue("UTF-8".equals(System.getProperty("file.encoding")));

        // and actually verify it is being used
        Charset charset = Charset.defaultCharset();
        Assert.isTrue(charset.equals(Charset.forName("UTF-8")));

        // locale
        // set and verify language

    }

}

score 6 · Accepted Answer · edited May 23 '17 at 12:08

6

I've used a ServletContextListener. In contextInitialized(..) TimeZone.setDefault(..) is called.

It won't be taken into account if you rely on the timezone in any constructor or @PostConstruct / afterPropertiesSet() though.

If you need it, take a look at this question

edited May 23 '17 at 12:08

Community

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answered Dec 11 '10 at 13:37

Bozho

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Thanks, that might work. However, I do have one InitializingBean and might need the timezone in it. If that is the case, does it make sense to put my `setDefault()` code into a `@PostConstruct`/`afterPropertiesSet()` instead? Are these InitializingBeans executed in the order defined in the spring xml file? – Tauren Dec 11 '10 at 23:48
You can try using the `order` attribute of beans. or see the answer I linked. – Bozho Dec 12 '10 at 06:42

M. Justin · Answer 3 · 2020-04-16T00:10:29.367

It may make sense to ensure that these are set before any beans are processed or initialized, as any beans created before this code is run could end up using the previous system default values. If you are using Spring Boot, you could do this in the main method before even initializing Spring:

@SpringBootApplication
public class Application {
    public static void main(String[] args) {
        Locale.setDefault(Locale.US);
        TimeZone.setDefault(TimeZone.getTimeZone("America/New_York"));

        SpringApplication.run(Application.class, args);
    }
}

If this needs to be run as part of a context that doesn't call the main method, e.g. in a JUnit integration test, you would need to make sure that it's called:

@SpringBootTest
public class ApplicationTest {
    @BeforeClass
    public static void initializeLocaleAndTimeZone() {
        // These could be moved into a separate static method in
        // Application.java, to be called in both locations
        Locale.setDefault(Locale.US);
        TimeZone.setDefault(TimeZone.getTimeZone("America/New_York"));
    }

    @Test
    public void applicationStartsUpSuccessfully() {
    }
}

score -6 · Answer 4 · answered Jan 24 '17 at 07:57

-6

How about standalone spring boot application? The java application looks like:

@SpringBootApplication
@EnableScheduling
@EnableConfigurationProperties(TaskProperty.class)
public class JobApplication {

/*  @Autowired
    private TaskProperty taskProperty;
*/  
    public static void main(String[] args) {
        SpringApplication.run(JobApplication.class, args);
    }
}

answered Jan 24 '17 at 07:57

richard

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This is not a relevant answer. – nixgadget Feb 20 '17 at 10:23

Initialize default Locale and Timezone with Spring configuration

4 Answers4

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