Why my function can't see this arrays strings

Question

Please help me find bug in my code. Why my function can't see varaibles, which is holded outside function?

    $file['folder'] = "/files/"; 
    $file['file'] = "myFile.txt";
    $file['ip'] = "http://127.0.0.1:1234";

function patToFile($sql,$action){
    $path = $file['ip'] . "/" . $file['folder'] . "/" . $file['file'];
    return $path;
}

When I use pathTofile(); it returns "//". So it cant see variable outside.

Why?
How I can fix this?

EDIT: I'm using global $file; inside function, to tell function use global variables.

1. Read about the [scope of variables](http://php.net/manual/en/language.variables.scope.php) in PHP. 2. Pass the array as argument to the function. — axiac, May 25 '17 at 13:44

score 2 · Accepted Answer · answered May 25 '17 at 13:56

Method 1

$file['folder'] = "/files/"; 
$file['file'] = "myFile.txt";
$file['ip'] = "http://127.0.0.1:1234";

function patToFile($sql,$action,$file){
    $path = $file['ip'] . "/" . $file['folder'] . "/" . $file['file'];
    return $path;
}

//Call function, Suppose already $sql, $action
pathToFile($sql, $action, $file);

Method 2 using $GLOBALS if variable $file is global variable

$file['folder'] = "/files/"; 
$file['file'] = "myFile.txt";
$file['ip'] = "http://127.0.0.1:1234";

function patToFile($sql,$action){
    $path = $GLOBALS['file']['ip'] . "/" . $GLOBALS['file']['folder'] . "/" . $GLOBALS['file']['file'];
    return $path;
}

//Call function, Suppose already $sql, $action
pathToFile($sql, $action);

I'm using in function `global $file` and it makes array visible for function. Thank You for answer! :) — Цунский Никита, May 25 '17 at 13:58
Yes, At first I was going to write the same way but I changed my mind to use `$GLOBALS`, but they are same — Canh Nguyen, May 25 '17 at 14:01

score 0 · Answer 2 · answered May 25 '17 at 13:58

0

You can do this :

function patToFile($sql,$action) use ($file){
    $path = $GLOBALS['file']['ip'] . "/" . $GLOBALS['file']['folder'] . "/" . $GLOBALS['file']['file'];
    return $path;
}

answered May 25 '17 at 13:58

Yassine CHABLI

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Why my function can't see this arrays strings

2 Answers2