See if any value exists in list by looping

Question

I do not know what I am missing but I've tried 3 different ways to achieve basically the same thing. Looking at the code below, why does only 1 out of the 4 ways work. I want to see if a value (located in a list) exists inside another list. I checked this SO question but still not understanding why the code is failing to print True1 , True2, and True4.

l1 = ["bravo", "alhpa", "charlie"]

l2 = ["alpha"]


if l1[1] in l2:
    print "True1"  # does not work

if l1[1] == l2[0]:
    print "True2"  # does not work

if "alpha" in l2:
    print "True3"  # works

for outer in l1:
    for inner in l2:
        if outer == inner:
            print "True4"  # does not work

@khelwood yes it is, this was honestly just a complete oversight, but here come all the down votes. — Kervvv, May 29 '17 at 06:34

score 3 · Accepted Answer · answered May 29 '17 at 06:30

3

You have a typo: "alhpa" vs. "alpha"

answered May 29 '17 at 06:30

Shai

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HOW EMBARRASSING!!!! Thank you! They all print now. Will accept as answer once it allows me to. That is what happens when I stare at just one thing too long – Kervvv May 29 '17 at 06:32

See if any value exists in list by looping

1 Answers1