To find complete String is present or not...not sub string

Question

If my str2 (variable) is java. still i get output :-value present. i want to search only complete string not sub string. Is their any function which cheks for only complete string??

     $str2 ="javascript";

     $str1 ="abc def xyz in javascript ";

     if(stripos($str1,$str2) !== false) { 

        echo "value present";   

     }else{

     echo "noooo";

    }

yes its working fine.....if my $str2="java..my output is value present...but i don't want substring search — Yabes Nadar, Jun 21 '17 at 12:21
@YabesNadar do you want check for string like $str2 ="javascript is awesome "; to ? — Bibhudatta Sahoo, Jun 21 '17 at 12:28
my both the variable($str1 & $str2) are dynamic. only thing i want is that it should not match sub string — Yabes Nadar, Jun 21 '17 at 12:33

score 1 · Accepted Answer · answered Jun 21 '17 at 12:34

If you want to search a string like this $str2 ="javascript is awesome ";

Then try below code

$str2 ="javascript is awesome";
$str1 ="abc def xyz in javascript ";
$filterKeys = explode(' ', $str2);
$regexp='';
foreach ($filterKeys as $word) {
    $word = trim($word);
    if ($word) {
        $regexp = $regexp . "$word|";
    }
}
$regexp = chop($regexp, '|');
preg_match("/\b($regexp)\b/i", $str1, $res);
if(!empty($res)) {
    echo "value present";
}else{
    echo "noooo";

}

I think it will help you.

Make sure to call [`preg_quote()`](http://php.net/manual/en/function.preg-quote.php) on any user-provided values when dynamically creating a regular expression. — Phylogenesis, Jun 21 '17 at 12:38

lalithkumar · Answer 2 · 2017-06-21T12:47:44.530

0

Here if you pass the full name in $str only it will return value present.

    $str1 ="abc def xyz in javascripts ";
    $array=explode(" ",$str1);
    $str='javascripts';
    if (in_array($str,$array)){
        echo "value present"; 
    }else{
        echo "noooo";
    }

edited Jun 21 '17 at 12:47

answered Jun 21 '17 at 12:28

lalithkumar

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To find complete String is present or not...not sub string

2 Answers2