Adressing PHP array decoded from JSON

Question

I'm loading a JSON array and decode it to an PHP array

$jsonfile = file_get_contents('https://www.alphavantage.co/query?function=TIME_SERIES_INTRADAY&symbol=MSFT&interval=15min&outputsize=full&apikey=demo'); 
$jsonarray = json_decode($jsonfile); 
var_dump($jsonarray);

So far so good I get an array that looks like that:

object(stdClass)#1 (2) { 
    ["Meta Data"]=> object(stdClass)#2 (5) { 
        ["1. Information"]=> string(49) "Daily Prices (open, high, low, close) and Volumes" 
        ["2. Symbol"]=> string(5) "AAWVX" 
        ["3. Last Refreshed"]=> string(10) "2017-06-30" 
        ["4. Output Size"]=> string(9) "Full size" 
        ["5. Time Zone"]=> string(10) "US/Eastern" 
    } 
    ["Time Series (Daily)"]=> object(stdClass)#3 (105) { 
        ["2017-06-30"]=> object(stdClass)#4 (5) { 
            ["1. open"]=> string(7) "10.5100" 
            ["2. high"]=> string(7) "10.5100" 
            ["3. low"]=> string(7) "10.5100" 
            ["4. close"]=> string(7) "10.5100" 
            ["5. volume"]=> string(1) "0" 
        } 
        ["2017-06-29"]=> object(stdClass)#5 (5) { ["1. open"]=> string(7) "10.4800" ["2. high"]=> string(7) "10.4800" ["3. low"]=> string(7) "10.4800" ["4. close"]=> string(7) "10.4800" ["5. volume"]=> string(1) "0" } 
        ["2017-06-28"]=> object(stdClass)#6 (5) { ["1. open"]=> string(7) "10.5600" ["2. high"]=> string(7) "10.5600" ["3. low"]=> string(7) "10.5600" ["4. close"]=> string(7) "10.5600" ["5. volume"]=> string(1) "0" } ...

But when I try to adress the array like

var_dump($jsonarray['Meta Data']);

It doesn't work.

Either decode with `true` as second arg or use `$jsonarray->{'Meta Data'}->{'1. Information'}` — AbraCadaver, Jul 03 '17 at 20:55
http://php.net/manual/en/function.json-decode.php See the second argument to the function. Looks like you need it to be true. — ckimbrell, Jul 03 '17 at 20:56
You need to get in the habit of [accepting answers](http://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer-work) which help you to solve your issues. You'll earn points and others will be encouraged to help you. — Jay Blanchard, Jul 03 '17 at 21:03
Possible duplicate of [How do I extract data from JSON with PHP?](https://stackoverflow.com/questions/29308898/how-do-i-extract-data-from-json-with-php) — user3942918, Jul 31 '18 at 20:37

GrumpyCrouton · Accepted Answer · 2018-07-31T20:34:32.237

10

This is because json_decode() with no parameters attempts to convert your json string to an stdClass object. If you want to convert it to an array, you need to set the 2nd parameters (the $assoc boolean) to true:

$json = file_get_contents('LINK TO JSON OUTPUT'); 
$array = json_decode($json, true);

edited Jul 31 '18 at 20:34

answered Jul 03 '17 at 20:49

GrumpyCrouton

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Adressing PHP array decoded from JSON

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