Why does an in-loop print() output after the loop is completed?

Question

In the code below, the diamond characters (\4) are not printed immediately but after the loop is completed. Any ideas why?

from os import system
from time import sleep

def load():
    system('cls')
    i = 0
    sleep(1)
    print("\n\n\n\n\n\n\n\n\n\n\n\t\t\t Loading ", end=' ')
    for i in range(6):
        sleep(1)
        print("\4", end=' ')
        sleep(2) 
load()

Could not reproduce in Python 2 (using `from __future__ import print_function`) — SiHa, Jul 06 '17 at 06:56

rinkert · Accepted Answer · 2017-07-06T09:15:34.367

The printing is working in Python IDLE for me. In Windows cmd it does not. Removing the end=' ' solves this, but then each diamond gets printed on a new line.

Depending on your OS you have to change the line ending. Check this page for more info on that: Python print on same line

This is working on Windows:

from os import system
from time import sleep
import sys

def load():
    system('cls')
    i = 0
    sleep(1)
    sys.stdout.write("\n\n\n\n\n\n\n\n\n\n\n\t\t\t Loading ")
    for i in range(6):
        sleep(1)
        sys.stdout.write("\4")
        sys.stdout.flush()
        sleep(2)

load()

Why does an in-loop print() output after the loop is completed?

1 Answers1