OR operator not working in javascript

Question

what is alternative of

if(s!=1||s!=2||s!=3)
 {

   alert("SUCCESS");
  }

It is not working. So Please suggest.

works just fine. here is a [fiddle](https://jsfiddle.net/kukicvladimir/vbeLdtpg/1/) — Kukic Vladimir, Jul 16 '17 at 14:19
Presumably it doesn't work because there is no value of s that will not alert ... if you want s to be anything but 1,2,3 use &&. — Alex K., Jul 16 '17 at 14:21
https://stackoverflow.com/questions/359494/which-equals-operator-vs-should-be-used-in-javascript-comparisons - verify you convert types — dmitryro, Jul 16 '17 at 14:21
If something isn't `1`, OR if it isn't `2` ... is never true, it can't be either not one thing, or not another, the logic seems flawed, you probably wanted `&&` — adeneo, Jul 16 '17 at 14:22
@GerardoFurtado - yes of course, always true, not never true. — adeneo, Jul 16 '17 at 14:41

score 3 · Accepted Answer · answered Jul 16 '17 at 14:21

It's very unlikely that you wanted:

 if(s!=1||s!=2||s!=3)

Since for all values of s, this is always true.

|| means that the expression is true if either the left side or right side is true.

Maybe you wanted it to be true if s was not 1, 2, or 3. Even though you use the word "or" in that sentence, in a logic expression, you say "s is not equal to 1 AND s is not equal to 2 AND s is not equal to 3"

If that's what you want, then the code is

if (s!=1 && s!=2 && s!=3)

OR operator not working in javascript

1 Answers1