Can I use generator-function with arrow function?

Question

I wander if it's possible to use arrow function with generators like this:

app.use( *() => {
    ...body of function
});

Thanks!

Yes I am, you're basically asking if you can run the code you wrote, go ahead, try it yourself and see what happens ! Then, when you'll see it doesn't work, either do your own searches, or look at @hsz 's answer. — Serge K., Jul 21 '17 at 08:14
If needed, you can easily omit generator function name to achieve anonymous function, like `app.use(function*() { /* body of generator */ })`. More discuss here: https://stackoverflow.com/a/34108006/7878274 — Vladislav Ihost, Jul 21 '17 at 08:15
Yes, but for arrows function maybe works like `*() => {}" or "()* => {}` and so on.. You see? It's difference to be smart and think you're smart... — Carnaru Valentin, Jul 21 '17 at 08:16

score 3 · Accepted Answer · edited Jul 21 '17 at 08:04

3

No, it's not possible to make it shorter than described in the documentation:

function* name([param[, param[, ... param]]]) {
   statements
}

Ref: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/function*

edited Jul 21 '17 at 08:04

Kaiido

123,334
13
219
285

answered Jul 21 '17 at 07:58

hsz

148,279
62
259
315

Elmer · Answer 2 · 2023-01-21T20:53:42.943

You can, but not really in a nice way. It's not shorter and does not look that pretty. Check this out:

function* iterable(arg) {
    yield* [];
}

async function* asyncIterable(arg) {
    yield* [];
}

const arrowIterable = arg => {
    return {
        *[Symbol.iterator]() {
            yield* [];
        },
    };
};

const arrowAsyncIterable = arg => {
    return {
        async *[Symbol.asyncIterator]() {
            yield* [];
        },
    };
};

This works because an iterable is basically an object with the Symbol.iterator or Symbol.asyncIterator set to an iterator. A generator is an iterator!

Enjoy!

Can I use generator-function with arrow function?

2 Answers2