Simple elif statement

Question

When I run this code it always goes to the else. Even when I choose 1, 2, or 3. How can I achieve a proper if, elif else statement?

def main():
    name = input("What is your name?")
    print("Hello", name)
    choice = int
    choice = 0
    choice = input("Please choose a number from the following options: \n 1. Paper \n 2. Rock \n 3. Scissors")
    print (choice)

    if choice == 1:
        print ('You chose number 1')
    elif choice == 2:
        print ('You chose number 2')
    elif choice == 3:
        print ('You chose number 3')
    else:
        print ('Invalid Entry Mush')
    return

main()

Please tag as Python. There are some unnecessary lines of code in your script, but the problem is the input is a string and not an integer. wrap the numbers in the conditions with quotes. — Yuval Ben-Arie, Jul 21 '17 at 13:13

score 1 · Answer 1 · answered Jul 21 '17 at 13:12

1

input returns a string. You will need to cast it to an int so that your elif options that check for ints are triggered:

choice = int(input("Please choose a number from the following options: \n 1. Paper \n 2. Rock \n 3. Scissors"))

By the way the two lines before that one are unnecessary.

answered Jul 21 '17 at 13:12

Cary Shindell

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8
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Thank a lot for taking the time to reply! Very helpful :-) – David Jul 21 '17 at 13:59
No problem! Be sure to accept answer if your question has been resolved ;) – Cary Shindell Jul 21 '17 at 14:04

score 0 · Accepted Answer · answered Jul 21 '17 at 14:03

0

Or you can put your if statements between quotes: ex: if choice == "1" print("nr 1") elif choice == "2" so on ..

answered Jul 21 '17 at 14:03

ricristian

466
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17

Simple elif statement

2 Answers2