Why does Python 3 re.findall fail to find all matches here?

Asked Jul 22 '17 at 20:38

Active Jul 22 '17 at 20:40

Viewed 454 times

I'm using Python 3's re.findall to find all occurrences of a substring within a string:

import re
full_string = 'ABCDCDC'
sub_pattern = 'CDC'
re.findall(sub_pattern, full_string)

re.findall only finds ['CDC'], however, the pattern CDC occurs 2 times in the full string.

Why isn't re.findall finding all occurrences of CDC here? What's needed so that re correctly finds all occurrences?

asked Jul 22 '17 at 20:38

T. Webster

1

Don't forget to take a look at David C answer that is also interesting in the first linked question. – Casimir et Hippolyte Jul 22 '17 at 20:55
I'm using python 3.4 which doesn't have the new `regex` module to use that answer. – T. Webster Jul 23 '17 at 23:24
1

It isn't related to the python version, you have to install the module: [the link](https://pypi.python.org/pypi/regex) (use `sudo pip3 install regex` under linux) – Casimir et Hippolyte Jul 23 '17 at 23:37
The example comes from https://www.hackerrank.com/challenges/find-a-string. I ended up solving it without `regex`; it's probably(?) not an allowed library. – T. Webster Jul 24 '17 at 02:42

0 Answers0