Convert datetime to time in python

Question

I have:

test_date = "2017-07-20-10-30"

and then use:

day = datetime.strptime(test_date[11:], "%H-%M")

which gives me

1900-01-01 10:30:00

How do I just get: 10:30:00 as type datetime.time?

Possible duplicate of [Converting string into datetime](https://stackoverflow.com/questions/466345/converting-string-into-datetime) — fredtantini, Jul 23 '17 at 08:02

Cory Madden · Accepted Answer · 2017-07-23T07:44:33.573

15

You can use the strftime method of the datetime object like this:

day.strftime('%H:%M')

Ok, I misunderstood. Use day.time() to get a time object.

edited Jul 23 '17 at 07:44

answered Jul 23 '17 at 07:41

Cory Madden

But this returns string. I still want – Mat.S Jul 23 '17 at 07:43
9

oh, use `day.time()` – Cory Madden Jul 23 '17 at 07:44
What if I have a Pandas Series of datetime objects and I want time? – AstroFloyd Jun 14 '20 at 19:21
I wanted the above for time-only tick labels in matplotlib plots, which can be achieved as explained in [this answer](https://stackoverflow.com/a/32973263/1386750). – AstroFloyd Sep 07 '20 at 16:20

hiro protagonist · Answer 2 · 2017-07-23T07:50:05.457

you can parse your string using datetime.strptime to a datetime object and then call .time() on that to get the time:

from datetime import datetime

strg = "2017-07-20-10-30"

dt = datetime.strptime(strg, '%Y-%m-%d-%H-%M')
tme = dt.time()
print(tme)  # 10:30:00

of course you can also chain these calls:

tme = datetime.strptime(strg, '%Y-%m-%d-%H-%M').time()

2 Answers2