Compare 2 arrays and remove duplicates

Question

I am trying to compare 2 arrays using jquery and remove duplicates from that.
This is my code.Is this logic correct?

var list1 = [6, 7, 3, 4, 1, 2];
var list2 = [2, 4, 6, 5, 1, 9, 8, 7, 8];

var newArray = [];
var index1, index2;
$.each(list1, function(i, value)) {
  index1 = $.inArray(list1[i]);
  index2 = $.inArray(newArray[i]);
  if (index2 == -1) {
    newArray.push(list2[i]);
  }
}

Expected output:

[3,5,9,8]

The `i` belongs to `list1`, but you use it with `list2`, so your code would fail if `list1` contains more elements then `list2`. — t.niese, Jul 25 '17 at 10:50
Possible duplicate of [JavaScript array difference](https://stackoverflow.com/questions/1187518/javascript-array-difference) — Pierre Granger, Jul 25 '17 at 10:52
Possible duplicate of [Get the unique values from two arrays and put them in another array - Jquery](https://stackoverflow.com/questions/15912538/get-the-unique-values-from-two-arrays-and-put-them-in-another-array-jquery) — Alive to die - Anant, Jul 25 '17 at 11:11

Bibhudatta Sahoo · Accepted Answer · 2017-07-25T11:17:03.560

4

Try like this

<script type="text/javascript">
    var arr1=[6,7,3,4,1,2];
    var arr2=[2,4,6,5,1,9,8,7,8];
    $(document).ready(function(){
        var newArray=$.merge($(arr1).not(arr2).get(),$(arr2).not(arr1).get());
        console.log(newArray);
    });
</script>

It give out put as

[ 3, 5, 9, 8,8 ]

Another answer with using $.each,$.inArray and .push only Try this

var list1 = [6, 7, 3, 4, 1, 2];
var list2 = [2, 4, 6, 5, 1, 9, 8, 7, 8];

var newArray = [];
$.each(list1, function(i, value){
    if($.inArray(value,list2)==-1){
        newArray.push(value);
    }
});
$.each(list2, function(i, value){
    if($.inArray(value,list1)==-1){
        newArray.push(value);
    }
});
newArray=$.unique(newArray);
console.log(newArray);

It give out put as

[ 3, 5, 9, 8]

edited Jul 25 '17 at 11:17

answered Jul 25 '17 at 10:59

Bibhudatta Sahoo

4,808
2
27
51

Please give me suggestion for this question using `$.each`,`$.inArray` and `.push`. – krish Jul 25 '17 at 11:01
@krish try the second answer. – Bibhudatta Sahoo Jul 25 '17 at 11:17
here we are passing `list1` in $.each but why we are checking with `list2` ? – krish Jul 25 '17 at 11:37
1

We are chacking the value of `list1` is present in `list2` array or not . – Bibhudatta Sahoo Jul 25 '17 at 11:39
Instead of `$.unique` can we check like this `if($.inArray(value,list2)==-1 && $.inArray(list2,newArray==-1))` ?? – krish Jul 26 '17 at 11:45
`$.unique` is used to remove duplicate values in the array. – Bibhudatta Sahoo Jul 26 '17 at 13:05

score 1 · Answer 2 · answered Jul 25 '17 at 10:55

1

Concat the arrays and filter the two:

var list1=[6,7,3,4,1,2];
var list2=[2,4,6,5,1,9,8,7,8];

function removeDuplicates(arr1, arr2) {
    return [...new Set(arr1.concat(arr2).filter(e => ! (arr2.includes(e) && arr1.includes(e))))];
}

console.log(removeDuplicates(list1, list2));

answered Jul 25 '17 at 10:55

baao

71,625
17
143
203

Please give me suggestion for this question using `$.each`,`$.inArray` and `.push`.please. – krish Jul 25 '17 at 11:01

score 1 · Answer 3 · answered Jul 25 '17 at 11:09

1

This is a way similar to yours...

var list1=[6,7,3,4,1,2];
var list2=[2,4,6,5,1,9,8,7,8]; 
var list = list1.concat(list2);
var uniqueList = []; 
$.each(list , function(i, el){
  if($.inArray(el, uniqueList) === -1) 
   {
    uniqueList .push(el);
   }
});

answered Jul 25 '17 at 11:09

Ardit

376
4
9

It wont produce `[3,5,9,8]` as result. – Szabolcs Jul 25 '17 at 11:14
Then what it will produce?what is the list here? – krish Jul 25 '17 at 11:16

score 1 · Answer 4 · answered Jul 25 '17 at 11:16

Try this fiddle

var list1 = [6, 7, 3, 4, 1, 2];
var list2 = [2, 4, 6, 5, 1, 9, 8, 7, 8];
var newArray = [];
$.each(list1, function(i, value) {
  if ($.inArray(value, list2) == -1) {
    newArray.push(value);
  }
});
$.each(list2, function(i, value) {
  if ($.inArray(value, list1) == -1) {
    newArray.push(value);
  }
});
console.log(newArray);

Used $.each,$.inArray and .push as requested

Compare 2 arrays and remove duplicates

4 Answers4