Why does the UnboundLocalError get raised on this code?

Asked Jul 30 '17 at 09:15

Active Sep 09 '22 at 16:11

Viewed 23 times

I am creating a computer login code that will lock you out after an amount of faults. But the code returns the UnboundLocalError on the attempts variable. I have made attempts global but it hasn't changed anything. It is raised on

if (user == username) and (passwd == password):
    `print("You are logged on")`
else:
    attempts += 1
    if attempts == 3:
        print("You have been locked out of your computer")
        time.sleep(60)

All of this is in a function and attempts is made global. Can someone help?

edited Jul 30 '17 at 10:55

asked Jul 30 '17 at 09:15

ProgrammingIsFun

You should provide more details about your code, with that little information it is hard to provide you any help. – Stephan Jul 30 '17 at 09:26
This code would raise a `NameError`, not an `UnboundLocalError` – juanpa.arrivillaga Jul 30 '17 at 09:27
can you please share the code snippet so that the problem can be looked upon! – Keerthana Prabhakaran Jul 30 '17 at 10:24
"and attempts is made global" No, it isn't. If it were, `global` would appear *in this part of the code*. – Karl Knechtel Sep 09 '22 at 16:11

Why does the UnboundLocalError get raised on this code?

0 Answers0