Iterating through YAML list in python

Question

I'm trying to read a YAML file and print out the list I have on there in order of what it is in the file.

So YAML:

b: ...
a: ...

And my python is:

for key, value in yaml.load(open(input_file)).items():
    print(str(key))

The output becomes:

a
b

However I need it to be b then a. I've also tried iteritems(), and I get the same result.

Why do you do `print(str(key))`, does that give a different result from `print(key)`? — Anthon, Aug 02 '17 at 14:03

Anthon · Accepted Answer · 2017-08-02T14:05:06.553

5

If your YAML file contains:

b: 2
a: 1

Then parsing like this:

from ruamel.yaml import YAML

yaml = YAML()
input_file = 'input.yaml'

for key, value in yaml.load(open(input_file)).items():
    print(str(key))

will print b first. If you however use the (faster):

yaml = YAML(typ='safe')

this is not guaranteed, as the order of mapping keys is not guaranteed by by the YAML specification.

If you are using YAML 1.1 and PyYAML, there is no such guarantee of order, but then you should not be using yaml.load() in the first place, because it is unsafe.

edited Aug 02 '17 at 14:05

answered Aug 02 '17 at 13:58

Anthon

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Thanks, that makes sense. I'll need to take a closer look at YAML in general to figure this out bette, but thanks for pointing me in the right direction :) – Rikg09 Aug 04 '17 at 10:12

score 1 · Answer 2 · answered Aug 02 '17 at 13:55

1

yaml.load in this case just returns a dict, which by default is unordered. If you care about preserving order, you'd need to use an OrderedDict, see here for an example of how to do that.

answered Aug 02 '17 at 13:55

thaavik

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Iterating through YAML list in python

2 Answers2