Get one item from an array based on a condition

Question

I have an array with different values (in JSON structure), I need to get one item on the array based on another value.

This is what I did so far:

var orders= [{
    "id": 1,
    "order": "11"
  },
  {
    "id": 2,
    "order": "22"
  },
  {
    "id": 3,
    "order": "33"
  }];
var order = $.grep(orders, function (e) { return e.order === '22'; })[0];
var orderID = order ? order.id : 0;

Is this the simplest way to do it?

What kind of browser support do you need? ES6 introduces `find` for `var order = orders.find(e => e.order === order)`. — Ry-, Aug 18 '17 at 07:08
Possible duplicate of [Javascript: How to filter object array based on attributes?](https://stackoverflow.com/questions/2722159/javascript-how-to-filter-object-array-based-on-attributes) — Dr. X, Aug 18 '17 at 07:15

score 4 · Accepted Answer · answered Aug 18 '17 at 07:08

4

With ES6, you could use Array#find

var orders= [{ id: 1, order: "11" }, { id: 2, order: "22" }, { id: 3, order: "33" }],
    order = orders.find(o => o.order === "22"),
    orderID = order ? order.id : 0;

console.log(orderID);

answered Aug 18 '17 at 07:08

Nina Scholz

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1

Thank you, that's much simpler than the `grep` function, thank you! – user3378165 Aug 18 '17 at 07:21
If I need to get the `id` of the found `order` I need the second line of code? That can't be done on the `find` function? – user3378165 Aug 18 '17 at 07:24
1

`find` returns `undefined`, if no item is found. you need a check later and get the id, or a default value – Nina Scholz Aug 18 '17 at 07:27

Get one item from an array based on a condition

1 Answers1