i search for a way to call a method by its string name.
#include <iostream>
#include <string>
class myClass{
    public:
        void method1(int run){
            std::cout << run << std::endl;
        }
        void method2(int run){
            std::cout << run << std::endl;
        }
};
int main(){
    myClass mc;
    std::string call;
    call = "method1";
    mc.call(1);
    call = "method2";
    mc.call(2);
}
But the result, is
‘class Myclass’ has no member named ‘call’
I need response "1" and "2";
EDIT :: Very thank's for your help, i get the next solution (i don't know is good for all cases );
#include <iostream>
#include <string>
class myClass{
public:
    void method1(int run){
        std::cout << "Loaded method => " << run << std::endl;
    }
    void method2(int run){
        std::cout << "Loaded method => " << run << std::endl;
    }
    void _loadMethods(int method, int params){
        switch(method) {
            case 1:
                method1(params);
                break;
            case 2:
                method2(params);
            break;
            default:
                 break;
        }
    }
};
int main(){
    myClass mc;
    std::string method;
    method = "method2";
    if(method == "method1"){
         mc._loadMethods(1, 1);
    }
    if(method == "method2"){
        mc._loadMethods(2, 2);
    }
}
Thank's
 
    