How to parsing JSON like this?

Question

I have json data format like

{
   "status":200,
   "message":"ok",
   "response": {"result":1, "time": 0.0123, "values":[1,1,0,0,0,0,0,0,0]
   }
}

I want to get one value of values array and put it on textView in eclipse. Look my code in eclipse

protected void onPostExecute (String result){
try {
JSONobject json = new JSONObject(result);
tv.setText(json.toString(1));
}catch (JSONException e){
e.printStackTrace();
}
}

You code seems to be missing some parts. Where is the `try` and where does the function close? — nalyd88, Sep 13 '17 at 02:18

score 1 · Answer 1 · answered Sep 13 '17 at 02:53

1

You can use GSON

Create a POJO for your response

public class Response{
   private int result;
   private double time;
   private ArrayList<Integer> values;

   // create SET's and GET's
}

And then use GSON to create the object you desire.

protected void onPostExecute (String result){
  try {
     Gson gson = new GsonBuilder().create();
     Response p = gson.fromJson(result, Response.class);
     tv.setText(p.getValues());
  }catch (JSONException e){
    e.printStackTrace();
  }
}

answered Sep 13 '17 at 02:53

joao86

2,056
1
21
23

Thank you very much joao86's, your code have been helped me, that's working but i want get values array by index. What sould i do for this ? Please – ahsanasha 07 Sep 13 '17 at 06:27
@ahsanasha07 what do you mean by `get values array by index.`? If you want to get the value in a certain position of the array, just do `p.getValues().get(position)` – joao86 Sep 13 '17 at 14:34
Yes sir, i want get the value in certain position of the array. I try p.getValues().get(position) not working. – ahsanasha 07 Sep 15 '17 at 14:52
what happens when you use it? – joao86 Sep 15 '17 at 14:59
When i running project, application is close itself – ahsanasha 07 Sep 15 '17 at 15:14
print to the log what the result of p.getValues() – joao86 Sep 15 '17 at 15:34
Java.lang.NullPointerException at skr.example.skripsi.home$HttpAsyncTask.onPosExecute(home.java: 215) at skr.example.skripsi at android.os.AsyncTask.finish(AsynchTask.java:417) – ahsanasha 07 Sep 15 '17 at 16:15
what is the string you are receiving onPostExecute? – joao86 Sep 15 '17 at 16:17

score 0 · Answer 2 · answered Sep 13 '17 at 02:41

You can use jackson library for json parsing.

ObjectMapper mapper = new ObjectMapper();
Map map = mapper.readTree(json);
map.get("key");

You can use readTree if you know json is an instance of JSONObject class else use typeref and go with readValue to get the map.

score 0 · Answer 3 · answered Sep 13 '17 at 20:04

0

    protected void onPostExecute (String result){
    try {
    JSONObject json = new JSONObject(result);
    JSONObject resp = json.getJSONObject("response");
JSONArray jarr = resp.getJSONArray("values");
     tv.setText(jarr.get(0).toString(1));
    }catch (JSONException e){
     e.printStackTrace(); 
    }
     }

answered Sep 13 '17 at 20:04

Francis Nduba Numbi

2,499
1
11
22

Thank bro, now is working. I just change tv.setText(jarr.get(0).toStirng(1)); into tv.setText(jarr.get(0).toString()); done – ahsanasha 07 Sep 16 '17 at 04:32
You can vote me up if it helped. Or mark it as answered. – Francis Nduba Numbi Sep 16 '17 at 20:10

How to parsing JSON like this?

3 Answers3