How to pass one function as an argument into another function in C++?

Asked Sep 17 '17 at 14:24

Active Sep 17 '17 at 14:27

Viewed 58 times

Functions are said to be first class objects in C++. How is it possible to replicate the following pyhton code in C++?

def print_wrapper(a):
    print(a)

def execute_function(func, arg):
    return func(arg)

execute_function(print_wrapper, 'test_argument')

Please note that the function print_wrapper is passed as an argument into the function execute_function.

asked Sep 17 '17 at 14:24

Greg

3

Search for terms like "functor", "function object", "std::function", "function pointer" and "lambda function". – Jodocus Sep 17 '17 at 14:25
looks like preprocessor task, `#define print_wrapper(a) print(a)` or `#define execute_function(func, arg) func(arg)` – SHR Sep 17 '17 at 14:29
3

@SHR - No, no, definitely not! – StoryTeller - Unslander Monica Sep 17 '17 at 14:30

0 Answers0