How to parse String having decimal, negative decimal into integer?

Question

Under for loop i am getting string values like decimal,integer, negative decimal values, i want to convert all of them in integer with one if condition,

how to achieve this?

 for(WebElement rowElement:TotalRowCount)
        {
              List<WebElement> TotalColumnCount=rowElement.findElements(By.xpath("td/span"));
              int ColumnIndex=1;
              for(WebElement colElement:TotalColumnCount)
              {
                  String s=colElement.getText().replace("%", "");

                  if(!s.isEmpty()&&!s.equals("NA"))
                  {

                   System.out.println("Row "+RowIndex+" Column "+ColumnIndex+" Data "+s);

                  }
                  else{/*do nothing*/}
               }
              RowIndex=RowIndex+1;
         }

Possible duplicate of [How to convert a String to an int in Java?](https://stackoverflow.com/questions/5585779/how-to-convert-a-string-to-an-int-in-java) — iamsankalp89, Sep 19 '17 at 06:31
i dont know what string contains , it may conatin decimal, or integer, it is in loop i want if condition that should convert to integer — sameer joshi, Sep 19 '17 at 07:18

score 1 · Answer 1 · answered Sep 19 '17 at 06:22

1

int intnum= Integer.parseInt("1234");

See the Java Documentation for more information.

(If you have it in a StringBuilder (or the ancient StringBuffer), you'll need to do Integer.parseInt(myBuilderOrBuffer.toString()); instead).

answered Sep 19 '17 at 06:22

Zakaria Shahed

2,589
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For more info https://alvinalexander.com/java/edu/qanda/pjqa00010.shtml – Zakaria Shahed Sep 19 '17 at 06:23
"_i am getting string values like decimal,integer, negative decimal values_" you will not parse everything with that code – AxelH Sep 19 '17 at 06:34

score 1 · Answer 2 · answered Sep 19 '17 at 06:24

1

If you are expecting decimals, then you can use BigDecimal.

BigDecimal nm = new BigDecimal(s);
int required = nm.setScale(0, RoundingMode.DOWN).intValueExact();

answered Sep 19 '17 at 06:24

RP-

5,827
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Dev · Answer 3 · 2017-09-19T06:40:27.673

1

 for(WebElement rowElement:TotalRowCount)
        {
              List<WebElement> TotalColumnCount=rowElement.findElements(By.xpath("td/span"));
              int ColumnIndex=1;
              for(WebElement colElement:TotalColumnCount)
              {
                  String s=colElement.getText().replace("%", "");

                  if(!s.isEmpty()&&!s.equals("NA"))
                  {

                   System.out.println("Row "+RowIndex+" Column "+ColumnIndex+" Data "+s);
         int val = (int) Double.parseDouble(s); // ==> This is val in integer

                  }
                  else{/*do nothing*/}
               }
              RowIndex=RowIndex+1;
         }

edited Sep 19 '17 at 06:40

answered Sep 19 '17 at 06:27

Dev

6,628
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"_i am getting string values like decimal,integer, negative decimal values_" you will not parse everything with that code – AxelH Sep 19 '17 at 06:34
Changed please verify – Dev Sep 19 '17 at 06:40
Off course I would mention `java.lang.Math` class to be able to round based on OPs choice, using `Float` would even remove the casting (because `int Math.round(float)` ) ;) – AxelH Sep 19 '17 at 06:47

score 1 · Answer 4 · answered Sep 19 '17 at 07:50

You can check first that if a received String is numeric or not by the following method and put that method call as a condition in your if statement.

public static boolean isNumeric(String s) {
        if (s.isEmpty())
            return false;
        try {
            double d = Double.parseDouble(s);
        }
        catch (NumberFormatException nfe) {
            return false;
        }
        return true;
    }

So, your If condition in for loop should look something like if(isNumeric(s)){...}. Also, to parse these values only to the Integer you can cast them by Math.floor(Double.parseDouble(s) + 0.5d). I think that should solve the issue.

score 0 · Answer 5 · answered Sep 19 '17 at 06:23

0

Declare it above.

int result = 0;

As per your code ,

String s=colElement.getText().replace("%", "");
result = Integer.parseInt(s);

Now result holds the integer value that you need to check.

answered Sep 19 '17 at 06:23

FreedomPride

1,098
1
7
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"_i am getting string values like decimal,integer, negative decimal values_" you will not parse everything with that code. – AxelH Sep 19 '17 at 06:36

Shubhendu Pramanik · Answer 6 · 2017-09-19T06:56:48.823

0

As your input may be decimal,integer, negative try below code to get proper rounded off result:

String s = "-88.4";
int a = Math.round(Float.parseFloat(s));
System.out.println(a);

edited Sep 19 '17 at 06:56

answered Sep 19 '17 at 06:49

Shubhendu Pramanik

2,711
2
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1

you could simply do `Math.round(Float.parseFloat(s))` to remove the casting here, I doubt you would get a difference between `double` and `float`. – AxelH Sep 19 '17 at 06:52

How to parse String having decimal, negative decimal into integer?

6 Answers6