Python if else executing in a bad way

Question

I am new to python and trying to execute my code. Below is my code.

   def evod(number):
    if number % 2 == 0:
        print("The number is even")
    return"The number is odd"

print(evod(60))

Output is: 
The number is even
The number is odd

if I run this function it prints both lines. It should print a single one of those. Right? Why is this happening?

You need to indent your code. Specifically, the body of the `if` statement. — Christian Dean, Sep 19 '17 at 16:44
Indentation defines the code blocks in Python. Indent the first `print` and it will work. — norok2, Sep 19 '17 at 16:44
You may also find [this](https://stackoverflow.com/questions/45621722/im-getting-an-indentationerror-how-do-i-fix-it) question and answer helpful. — Christian Dean, Sep 19 '17 at 16:44

score 1 · Answer 1 · answered Sep 19 '17 at 16:43

1

if c=="July":
    print("7/1/2017")
else:
    print("sorry")

Indentation matters in python!

answered Sep 19 '17 at 16:43

Kwahn

446
2
12

score 0 · Answer 2 · answered Sep 19 '17 at 16:44

0

if c == "July":
    print ("7/1/2017")
else:
    print ("sorry")

Correct your indentation

answered Sep 19 '17 at 16:44

Nimish Bansal

1,719
4
20
37

Thank you. I didn't know indention matters in python. – Dhruv Kadia Sep 19 '17 at 16:46

Python if else executing in a bad way

2 Answers2