Wrong value gets stored in the list

Question

This should store [1,2,3,4,5] in the list but it stores [1,1,1,1,1] instead:

l=[0]*5
for x in range(5):
    y=1
    l[x] = y
    y+=1
print (l)

you are initializing `y=1` inside for loop for every run. Take it outside loop. — Anil_M, Sep 20 '17 at 14:33
I am not sure this question was closed with the correct duplicate in mind; the error had not much to do with the immutability of ints; it is a typical new programmer question, and if SO can't answer, where can they turn to for help with this sort of mistakes? — Reblochon Masque, Sep 20 '17 at 14:42
the duplicate closure was a mistake. But there isn't much to answer there. For me it looks very much like a typo... Anil_M solved this in comments... — Jean-François Fabre, Sep 20 '17 at 21:47
Note that it's much more pythonic to do `l = list(range(1, 6))` — Justin, Sep 20 '17 at 21:49

Reblochon Masque · Accepted Answer · 2017-09-20T14:34:51.787

4

you must place y = 1 before entering the for loop:

my_list = [0] * 5
y = 1
for x in range(5):
    my_list[x] = y
    y += 1
print(my_list)

I changed the name of your list to my_list; using l is a source of confusion with 1...

edited Sep 20 '17 at 14:34

answered Sep 20 '17 at 14:33

Reblochon Masque

1 Answers1