How to check whether number is present in integer or not

Question

I have a number array.

E.g.

76543,65334,776958,8978,2436,232789

How can I check if the integers contain 7, 8 and 9, no matter the order?

E.g. 776958, 8978 and 232789 contain 7, 8 and 9, while 76543 only contains 7

`weather` is the wrong word in context and place you put it in. Solution for your problem convert to string and check with `contains` method — XtremeBaumer, Oct 02 '17 at 08:16
Do you mean the digits "7", "8" and "9" present in "8978" or? — Procrastinator, Oct 02 '17 at 08:18
Possible duplicate of [Java, Simplified check if int array contains int](https://stackoverflow.com/questions/12020361/java-simplified-check-if-int-array-contains-int) — Tom, Oct 02 '17 at 08:49
@Tom that suggested answer doesn't match the requirements. it checks if the array contains e.g. `7` as single value and not if any value inside the array contains all the integer — XtremeBaumer, Oct 02 '17 at 09:27
@XtremeBaumer That suggested question does what OP asks in his question. If he fails to explain what he ___actually___ needs in it, then it isn't my problem. — Tom, Oct 02 '17 at 09:30
@Tom he actually explains it. It is not his problem if you can't read the question properly (which **is your** problem) — XtremeBaumer, Oct 02 '17 at 09:33
@XtremeBaumer I guess you're right. That 4 others also thought this question unclear and that your answer is based on OPs comments doesn't matter in this case here. — Tom, Oct 02 '17 at 09:43

score 2 · Accepted Answer · answered Oct 02 '17 at 08:27

int[] ints = new int[] { 76543, 65334, 776958, 8978, 2436, 232789 };
for (int i : ints) {
    boolean containsAllThree = false;
    if (String.valueOf(i).contains("7") && String.valueOf(i).contains("8") && String.valueOf(i).contains("9"))
        containsAllThree = true;
    System.out.println(containsAllThree);
}

since you need don't need 789 but 7, 8 and 9 to be contained you have to perform 3 checks (i merged it into the IF condition)

Raúl Garcia · Answer 2 · 2017-10-02T08:29:17.467

0

You must convert this number to String and them compare is exist this subString. I think if you do this you can resolve.

boolean present = false;
int[] arr = {12123,432552,4534534};
for(int num : arr){
  String aux = Integer.toString(num);
  if(aux.contains("789"))
    present = true;
}

edited Oct 02 '17 at 08:29

answered Oct 02 '17 at 08:23

Raúl Garcia

282
3
18

1

`Int` doesn't exist. also it doesn't satisfy the requirements – XtremeBaumer Oct 02 '17 at 08:23
Is a little code error, now i change and is fix it. – Raúl Garcia Oct 02 '17 at 08:29
still your code doesn't meet the requirements. read the question carefully as well as the comments – XtremeBaumer Oct 02 '17 at 08:30
I will not fighting with you dude , if you prefer your solution i don't care but my solution, search if the **789** is in the items of a int array, that is the question. Bye man! – Raúl Garcia Oct 02 '17 at 08:36
1

`E.g. 776958, 8978 and 232789 contain 798.` your code will only work on `232789` but not the other two examples – XtremeBaumer Oct 02 '17 at 08:37

JensS · Answer 3 · 2017-10-02T09:00:07.653

Assuming you use JAVA8, you can use a stream. Map it to a String, then check if that String contains the numbers:

int[] arr = new int[] {1,2,3897};
System.out.println(Arrays.stream(arr)
                  .mapToObj(i -> String.valueOf(i))
                  .anyMatch(s -> s.contains("7") && s.contains("8") && s.contains("9")));

Depending on your exact needs, you could also use the stream to filter out the numbers that contain your numbers (or those that don't) with the .filter() method of the Stream.

int[] arr = new int[] {1,2,3897};
List list = Arrays.stream(arr)
            .filter(i -> String.valueOf(i).contains("7")  && String.valueOf(i).contains("8") && String.valueOf(i).contains("9"))
            .boxed()
            .collect(Collectors.toList());
System.out.println(list);

How to check whether number is present in integer or not

3 Answers3