my code is working fine till the first if statement after that my code is getting printed on screen

Question

 <?php

     $error="";$successMessage="";

    if($_POST) {

    $error="";

    if(!$_POST("email"))
    {
    $error .="An email address is required<br>";
    }//code works fine till here 

   //from here on the code gets printed on screen and is not working 
    if(!$_POST("content")){
    $error.="The content field is required<br>";
    }

    if(!$_POST("subject")){
    $error.="The subject is required<br>";
    }

    if ($_Post['email'] && filter_var($_POST("email"), FILTER_VALIDATE_EMAIL)===false) {
    $error .="$email is not a valid email address. <br>";
    }


    if($error !==""){

    $error='<div class="alert alert-danger" role="alert"><p><strong>There were error(s) in your form</strong></p>'. error . '</div>';
    }

    else
    {
    $emailTo="vibhorvimal5598@gmail.com";

    $subject=$_POST("subject");

    $content=$_POST("content");

    $headers="From:"$_POST('email');

    if(mail($emailTo,$subject,$content,$headers)){
    $successMessage='<div class="alert alert-danger" role="alert"><p><strong>Your message was sent</strong></p>'. error . '</div>';
    }

    }
    ?>

what is wrong in this code can anyone please explain because I already checked for the syntax and error and all . I don't know what is wrong and why this is happening. Can anyone please help me out and tell why the code is not working correctly after first if statement

Possible duplicate of [PHP code is not being executed, instead code shows on the page](https://stackoverflow.com/questions/5121495/php-code-is-not-being-executed-instead-code-shows-on-the-page) — Qirel, Oct 08 '17 at 09:35
Couple of issues I see: you are outputting 'error' twice instead of '$error'. Also, when setting $headers, you need to concatenate the two values together using a period. So that line should be "From:" . $_POST('email'); — Dan, Oct 08 '17 at 09:55

score 0 · Answer 1 · edited Jun 20 '20 at 09:12

Check You Comment Style Its Html Style Comment in php code

Check This how To Give Comments in Php: https://www.w3schools.com/PhP/php_syntax.asp

Updated:

Use $error like this to print instance of error.

// This is a single-line comment

# This is also a single-line comment

/*
This is a multiple-lines comment block
that spans over multiple
lines
*/

 <?php

     $error="";
     $successMessage="";

    if($_POST) {

    $error="";

    if(!$_POST("email"))
    {
    $error .="An email address is required<br>";
    } //code works fine till here 

   //from here on the code gets printed on screen and is not working 

    if(!$_POST("content")){
    $error.="The content field is required<br>";
    }

    if(!$_POST("subject")){
    $error.="The subject is required<br>";
    }

    if ($_Post['email'] && filter_var($_POST("email"), FILTER_VALIDATE_EMAIL)===false) {
    $error .="$email is not a valid email address. <br>";
    }


    if($error !==""){

    $error='<div class="alert alert-danger" role="alert"><p><strong>There were error(s) in your form</strong></p>'. $error . '</div>';
    }

    else
    {
    $emailTo="vibhorvimal5598@gmail.com";

    $subject=$_POST("subject");

    $content=$_POST("content");

    $headers="From:"$_POST('email');

    if(mail($emailTo,$subject,$content,$headers)){
    $successMessage='<div class="alert alert-danger" role="alert"><p><strong>Your message was sent</strong></p>'. $error . '</div>';
    }

    }
    ?>

sheraz · Answer 2 · 2017-10-08T21:30:40.020

Your code having lots of mistake . i have just rewrite your code. used below code.main mistakes are mentioned in below.

should used  $_POST['email'] instead of $_POST('email')
should used  $_POST['content'] instead of $_POST('content')
should used  $_POST['subject'] instead of $_POST('subject')
should used $error instead of error

if(!empty($_POST)) {

        if(!$_POST['email'])
        {
        $error .="An email address is required<br>";
        }//code works fine till here 

       //from here on the code gets printed on screen and is not working 
        if(!$_POST['content']){
        $error .="The content field is required<br>";
        }

        if(!$_POST["subject"]){
        $error .="The subject is required<br>";
        }

        if ($_POST['email'] && filter_var($_POST["email"], FILTER_VALIDATE_EMAIL)===false) {
        $error .="$email is not a valid email address. <br>";
        }

        if($error !==""){
        $error = '<div class="alert alert-danger" role="alert"><p><strong>There were error(s) in your form</strong></p>'. $error . '</div>';
        }

        else{
            $emailTo="vibhorvimal5598@gmail.com";

            $subject=$_POST["subject"];

            $content=$_POST["content"];

            $headers="From:".$_POST['email']."";

            if(mail($emailTo,$subject,$content,$headers)){
                $successMessage='<div class="alert alert-success" role="alert"><p><strong>Your message was sent</strong></p></div>';
            }
        }
    }

my code is working fine till the first if statement after that my code is getting printed on screen

2 Answers2

Updated: