I have a url that looks like this: www.example.com/website/link1/link2/link3
Which regex expression can I use to only get link3?
I found something similar but can't get it to work. I need to ignore the www.example.com/website/
^\/[^/]+\/([^/]+)\/
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Why not just split on `/` and take the last part? – tadman Oct 13 '17 at 20:45
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Your URL doesn't end in a slash, so you can simply capture the last chunk of content leading up to the final trailing slash:
/([^\/]+)$/
Note that you need the \ before the / to escape it, since it's embedded in / wrappers and some environments won't allow the embedded / without a preceding \.
If you need to support a trailing slash, you can add \/? ("an optional slash") before the $.
An example demo of this regex (with a useful explanation about it) can be found here: https://regex101.com/r/hRR4rw/1
Sean Werkema
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1Just add a suitable prefix to capture it, again going backward from the end of the string: `/([^\/]+)\/([^\/]+)$/` – Sean Werkema Oct 14 '17 at 15:00
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Normally you just anchor to the end:
/([^/]+)\/?$/
Where that matches /link/example/ as well as /link/example and returns example in both cases.
tadman
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