How do I initialize an array in this case?

Asked Oct 17 '17 at 16:24

Active Oct 17 '17 at 16:24

Viewed 41 times

I am not sure I am doing what I think I am doing: I want to pass an array to a function in the following way:

void gauss(double**, double**, int)
int main(){
   double **a,**b;

   a=new double*[n];
   b=new double*[n];
   int n;
   ...
   gauss(a,b,n)
   ...
   return 0;}
void gauss(double**a, double**b,int n){...}

My problem is that I can't assign values to my array. I tried

a[0][0]=1;
a[0][1]=2;
a[1][0]=3;
a[1][1]=4;

but I get a segmentation violation error.

How do I assign value to my array in this case.

asked Oct 17 '17 at 16:24

mattiav27

1

You have an "array" of pointers, but do you make these pointers actually point anywhere? – Some programmer dude Oct 17 '17 at 16:27
1

Also, I really recommend you start using [`std::vector`](http://en.cppreference.com/w/cpp/container/vector) whenever you need a "dynamic array". – Some programmer dude Oct 17 '17 at 16:27
once you fixed your code you should take a look at `std::vector` – 463035818_is_not_an_ai Oct 17 '17 at 16:27
He also seems to declare the variable n *after* he attempts to use it as the size of his arrays, so I'm not quite sure how this code can even compile... – Sean Burton Oct 17 '17 at 16:32

How do I initialize an array in this case?

0 Answers0