I can't figure out why the third function (i.e. doStuff3) isn't being called, so the console.log on fork should print "hello world!!!!"
const
doStuff = () => Future.of(["hello", "world"]),
doStuff2 = (x, y) => Future((resolve, reject) => resolve(`${x} ${y}`)),
doStuff3 = x => Future.of(`${x}!!!!`)
pipeK(doStuff, apply(doStuff2), doStuff3)().fork(console.log, console.error)
You can run it on Ramda REPL
Future doesn't suck like Promise
The broken Promise API allows you to then without handling errors
// uh, what happens if there's a problem ?
myPromise .then (console.log)
// proper use, but nothing forces you to specify 2nd argument
myPromise .then (console.log, console.error)
Of course you could .catch, but people often forget about that too – Future doesn't have these problems ...
Future forces you to specify the error path by making that the first parameter – in both the executor and the fork'ing function
const f1 = (...xs) =>
Future.of (xs)
const f2 = (x, y) =>
Future ((reject, resolve) => // REJECT comes first
resolve (x + y))
const f3 = x =>
Future.of (`${x} !!!`)
const myFuture =
pipeK (f1, apply (f2), f3)
("hello", "world")
// ERROR path first
myFuture.fork (console.error, console.log)
// logs: "helloworld !!!"
// returns: undefined
