PHP var into Javascript

Question

I have this php var, and I want to send it to php, but this way I can't

<?php
    $nb = rand(1,68);
?>
///////////////////////////////////////////////////////////////////////////
<script type="text/javascript"> jQuery ( '#dwDB-main' ).fadeTo ( 1, 0.01 );
    function random() {
    $rd = <?php $nb ?>;
    return $rd;
    }

Well, $rd isn't how you define a variable in javascript; https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/var — IsThisJavascript, Oct 20 '17 at 08:48
After all the fixes from other comments, your random() will still not return random number as you expected. It will always return the value it initially retrieved from PHP. You'd better use javascript Math.random() to really generate random number in javascript. — Anurat Chapanond, Oct 20 '17 at 08:51

Thielicious · Answer 1 · 2017-10-20T08:50:52.990

1

function random() {
    var rd = <?= $nb ?>;
    return rd;
}

edited Oct 20 '17 at 08:50

answered Oct 20 '17 at 08:48

Thielicious

4,122
2
25
35

This is the same OP wrote, and doesn't even work... – Naruto Oct 20 '17 at 08:50
should work now, I was still editing – Thielicious Oct 20 '17 at 08:58

score 0 · Accepted Answer · 2017-10-20T08:53:14.627

0

use echo for transfer the variable statement, actually its not able to print

<?php
$nb = rand(1,68);
?>
///////////////////////////////////////////////////////////////////////////
<script type="text/javascript"> jQuery ( '#dwDB-main' ).fadeTo ( 1, 0.01 );
    function random() {
        var $rd = <?php echo $nb; ?>;
        return $rd;
    }

edited Oct 20 '17 at 08:53

answered Oct 20 '17 at 08:48

`$rd = ;` are you sure this is correct? – IsThisJavascript Oct 20 '17 at 08:49
an semicolon is needed for sperating the php statement – Oct 20 '17 at 08:50
its $rd = ; – Oct 20 '17 at 08:51
No, `$rd` isn't how you define a variable in javascript – IsThisJavascript Oct 20 '17 at 08:51
sorry i missed var – Oct 20 '17 at 08:52

Mubashar Iqbal · Answer 3 · 2017-10-20T08:49:44.337

0

Try this.

<?php
    $nb = rand(1,68);
?>

<script type="text/javascript"> 
    function random() {
    var rd = <?php echo $nb ?>;
        return rd;
    }
    console.log(random());
</script>

And remember if you are using jquery then please add jquery script also.

edited Oct 20 '17 at 08:49

answered Oct 20 '17 at 08:49

Mubashar Iqbal

398
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18

PHP var into Javascript

3 Answers3