I have an array with a random elements. How can I check, is all that elements the same or not? Could it be possible with numpy.all ? Thanks
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                    1`len(set(my_array))==1` ? – PRMoureu Oct 21 '17 at 14:08
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                    Convert it to a set and check it is of size 1. Bah just beaten to it – Nick is tired Oct 21 '17 at 14:08
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                    1I am not agree with marking this post as duplicated because it is related to ```numpy.array``` and not to the ```list```. And, yes, you could check identity with ```numpy.all(your_array == your_array[0])``` – Timofey Chernousov Oct 21 '17 at 14:12
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                    2Another one: `numpy.unique(a).size == 1` – Daniel Oct 21 '17 at 14:19
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                    @TimofeyChernousov Unfortunately, it is such a basic question that I can't find a duplicate for it. I didn't read the question to the end, only the title and tags. – cs95 Oct 21 '17 at 14:21
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                    1@TimofeyChernousov: However, the first link I found without fail was the link to the np.all docs, which explicitly document this behaviour. If OP is not willing to put in that much effort to do a little research, this question doesn't deserve to be reopened. – cs95 Oct 21 '17 at 14:22
1 Answers
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        You can use all:
if all(i == a[0] for i in a):   
   #all the elements are the same
   pass
You can also use a set:
if len(set(a)) == 1:
   #all the elements are the same
   pass
 
    
    
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